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lina2011 [118]
3 years ago
11

What is the consumer's ability and desire to buy goods and services called? A. supply B. demand C. equilibrium

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
4 0

Answer:

demand

Step-by-step explanation:

dimulka [17.4K]3 years ago
4 0

Answer: Demand, B.

Step-by-step explanation:

Demand is the consumer's willingness to buy good or service by paying money for that.

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plz help me suzy spent 6 7/8 days working on her English paper 3 1/6 days on her science project and 1 1/2 days studying for her
malfutka [58]

Answer:

English time + Math Time =  6 7/8 + 1 4/8 =  7 7/8+4/8  =  8 3/8

8 3/8 - Science time = difference =   8 3/8- 3 1/6 = 5 5/24

She spent 5 5/24 days more on her English and Math test than Science

Step-by-step explanation:


5 0
4 years ago
1) g(n)= 3n - 4; Find g(-3)​
nalin [4]

Answer:

g(-3) = -13

Step-by-step explanation:

Plug in -3 for n in the equation:

g(n) = 3n - 4

g(-3) = 3(-3) - 4

Remember to follow PEMDAS. First, multiply, then subtract:

g(-3) = 3 * -3 = -9

g(-3) = -9 - 4

g(-3) = -13

-13 is your answer for g(-3).

~

4 0
3 years ago
Read 2 more answers
What is the mean cost of replacing brake pads for four different vehicles ai at the following prices $120,$235,$98,$142
Stels [109]

The mean is the average of a set of numbers.  So to do that:


add all the numbers 120+235+98+142=$595

Then divide that by the total number in the set, in this case it is 4.

$595/4= $148.75 assuming that the prices given are the final price of the job.

4 0
3 years ago
Solve The Equation <br> 4x×9y=7<br> 4x-9y=9
hoa [83]

Answer:

\large\boxed{x=\dfrac{9}{8}-\dfrac{\sqrt{109}}{8},\ y=-\dfrac{1}{2}-\dfrac{\sqrt{109}}{18}}\\or\\\boxed{x=\dfrac{9}{8}+\dfrac{\sqrt{109}}{2},\ y=-\dfrac{1}{2}+\dfrac{\sqrt{109}}{18}}

Step-by-step explanation:

\left\{\begin{array}{ccc}4x\times9y=7&(1)\\4x-9y=9&(2)\end{array}\right\\\\(2)\\4x-9y=9\qquad\text{subtract}\ 4x\ \text{from both sides}\\-9y=-4x+9\qquad\text{change the signs}\\9y=4x-9\qquad\text{substitute it to (1)}\\\\4x(4x-9)=7\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\(4x)(4x)+(4x)(-9)=7\\(4x)^2-36x=7\\(4x)^2-2(4x)(4.5)=7\qquad\text{add}\ 4.5^2\ \text{to both sides}\\(4x)^2-2(4x)(4.5)+4.5^2=7+4.5^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2

(4x-4.5)^2=7+20.25\\(4x-4.5)=27.25\to 4x-4.5=\pm\sqrt{27.25}\\\\4x-\dfrac{45}{10}=\pm\sqrt{\dfrac{2725}{100}}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{2725}}{\sqrt{100}}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{25\cdot109}}{10}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{25}\cdot\sqrt{109}}{10}\\\\4x-\dfrac{45}{10}=\pm\dfrac{5\sqrt{109}}{10}\qquad\text{add}\ \dfrac{45}{10}\ \text{to both sides}\\\\4x=\dfrac{45}{10}\pm\dfrac{5\sqrt{109}}{10}

4x=\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}\qquad\text{divide both sides by 4}\\\\x=\dfrac{9}{8}\pm\dfrac{\sqrt{109}}{8}\\\\\text{Put the values of}\ x\ \text{to (2):}\\\\9y=4\left(\dfrac{9}{8}\pm\dfrac{\sqrt{109}}{8}\right)-9\\\\9y=\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}-\dfrac{18}{2}\\\\9y=-\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}\qquad\text{divide both sides by 9}\\\\y=-\dfrac{1}{2}\pm\dfrac{\sqrt{109}}{18}

8 0
3 years ago
You roll a 4-sided die repeatedly. On your odd-numbered rolls (1st,3rd,5th, etc.) you are victorious if you get a 4. On your eve
Sunny_sXe [5.5K]

Answer:

E (Y) = 3

Step-by-step explanation:

If a 4-sided die is being rolled repeatedly; and the odd-numbered rolls (1st 3rd,5th, etc.)

The probability of odd number roll will be, p(T) = \frac{1}{2}

However, on your even-numbered rolls, you are victorious if you get a 3 or 4. Also, the  probability of even number roll, p(U) = \frac{1}{2}

In order to  calculate: E (Y); We can say Y to be the number of times you roll.

We know that;

E (Y) = E ( Y|T ) p(T) + E ( Y|U ) p(U)

Let us calculate E ( Y|T ) and E ( Y|U )

Y|T ≅ geometric = \frac{1}{4}

Y|U ≅ geometric = \frac{1}{2}

also; x ≅ geometric (p)

∴ E (x) = \frac{1}{p}

⇒ \frac{Y}{T} = 4 ; also \frac{Y}{U} = 2

E (Y) = 4 × \frac{1}{2} + 2 ×

        = 2+1

E (Y) = 3

7 0
3 years ago
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