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Ket [755]
3 years ago
6

Do not change the order of the numbers. You may put two numbers together to form a two-degit number.

Mathematics
1 answer:
LenKa [72]3 years ago
7 0
1 + 2 + 3 + 4 + 5 + 67 + 8 = 90

I think this is what you mean right?
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This is an urgent matter! Please help!
OLEGan [10]

Answer:

the answer is c a increasing line

6 0
2 years ago
Write the equation in slope intercept form<br> 2x+y=6
Rina8888 [55]

Answer: the slope intercept form of 2x+y=6 is y=-2+6

Step-by-step explanation:

2x+y=6  (subtract 2x from both sides)

-2x    -2x  (the -2x and the 2x cancel leaving...)

<u><em>y=-2x+6</em></u>  →( y equals negative two x plus six)

3 0
3 years ago
How do I do this please help I'm in tears
irakobra [83]
F(x) is vertically stretched by a factor of 5/4 matches w/ f(x)-5/4
f(x) reflects the x axis matches w/ -f(x)
f(x) is translated 5/4 units up matches with f(x)+5/4
f(x) translated 5/4 to the left matches w/ f(x)-5/4

I didn't really know about this one but it seemed kind of easy, what was your first guesses and did you forget to put one more or was the question like that.


Hope this is right :) or if someone else has a different answer but in the meantime, good luck :)
3 0
3 years ago
Read 2 more answers
Find the lengths of x <br><br> I tried everything I still got it wrong
Arlecino [84]

if the degrees in this triangle are truly 90-45-45, then the two unknown lengths are the same

and the pythagorean theorem holds anyways: a² + b² = c², where c is the longest side in a right triangle.

c is 16, so 16² is 256

2* a² = 256

I wrote 2 times s because a and b are of same length

devide each side by 2

a² = 128

take the root

a and b are:

\sqrt{128}  = 11.31378499

7 0
2 years ago
What is the product in simplest form? State any restrictions on the variable. Please show your work.
mote1985 [20]
You have the following expressions given in the problem above:

 (y^2/y-3)(y^2-y-6/y^2+y)
 
 By applying the exponents properties, you can simplify it, as it shown below:

 (y^2/y-3)(y^2-y-6/y^2+y)
 (y^4-y^3-6y^2)/(y^3+y^2-3y2-3y)
 (y^4-y^3-6y^2)/(y^3-2y2-3y)

 Then, you have:
 y^2(y^2-y-6)/y(y^2-2y-3)
 (y^2-y-6)/(y^2-2y-3)

 The answer is: (y^2-y-6)/(y^2-2y-3)

 


 
5 0
3 years ago
Read 2 more answers
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