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malfutka [58]
3 years ago
8

202" id="TexFormula1" title=" {2}^{x + 2 } = 9 \times( {2}^{x} ) - 2" alt=" {2}^{x + 2 } = 9 \times( {2}^{x} ) - 2" align="absmiddle" class="latex-formula">
pls how is this solved​
Mathematics
1 answer:
nataly862011 [7]3 years ago
7 0

Hello, please consider the following.

{2}^{x + 2 } = 9 \times( {2}^{x} ) - 2\\\\2^x \cdot 2^2=9\cdot 2^x-2\\\\(9-4)2^x = 2\\\\2^x=\dfrac{2}{5}\\\\\text{We take the ln.}\\\\xln(2)=ln(2)-ln(5)\\\\x=\dfrac{ln(2)-ln(5)}{ln(2)}=-1.32193...

Let me know if you need further explanation.

Thank you

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Answer:

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the vector is (3.064,-2.571)

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Jessica has an account with a credit union. Her account earns 2.7% simple interest yearly. Exactly a year and a half ago, she op
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Step2247 [10]
Solving for x

Since x<span> is on the right hand side of the </span>equation<span> switch the sides so it is on the left hand side of the </span>equation<span>.
</span><span>2x+yi=−14−3i
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Since <span>yi</span><span> does not contain the </span>variable<span> to solve for move it to the right-hand side of the </span>equation<span> by subtracting </span><span>yi</span><span> from both sides.
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</span>Divide<span> each </span>term<span> in the </span>equation<span> by </span><span>2.

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Solving for y

</span></span>Since y<span> is on the right hand side of the </span>equation<span> switch the sides so it is on the left hand side of the </span>equation<span>.
</span><span>2x+yi=−14−3i

</span>Since <span>2x</span><span> does not contain the </span>variable<span> to solve for move it to the right hand side of the </span>equation<span> by subtracting </span><span>2x</span><span> from both sides.
</span><span>yi=−2x−14−3i

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6 0
4 years ago
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lubasha [3.4K]

Answer:

the probability that more than 3 of them will have more than one ounce of mustard is 0.05975

Step-by-step explanation:

Given te data in the question;

let x rep the quantity of mustard on a hotdog ( in oz)

so

X → N ( u = 0.9, α² = 0.01 )

now P( more than one ounces of mustard on a hotdog) will be

P( X>1 ) = P( Z > ((1-0.9)/(√0.01)) ) = P( Z > 1 ) = 1 - P( Z < 1 )

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Also let Y rep the number of hotdogs that have more than one ounces of mustard, so

Y → Bin( n = 10, p = 0.15866 )

P( y = y ) = (¹⁰ _y) ( 0.15855)⁰ ( 1 - 0.15866 )^10-y, y = 0,1,2,3......, 10

so required probability = P(Y > 3) = 1 - P(Y ≤ 3)

= 1 - P(Y=0) - P(Y=1) - P(Y=2) - P(Y=3)

=1 -  (¹⁰ ₀) ( 0.15855)⁰ (1 - 0.15855)¹⁰⁻⁰ - (¹⁰ ₁) ( 0.15855)¹ (1 - 0.15855)¹⁰⁻¹ - (¹⁰ ₂) ( 0.15855)² (1 - 0.15855)¹⁰⁻² - (¹⁰ ₃) ( 0.15855)³ (1 - 0.15855)¹⁰⁻³

= 0.05975

Therefore the probability that more than 3 of them will have more than one ounce of mustard is 0.05975

4 0
3 years ago
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