Question

What is the coordinate of point P on the line segment AB that is 3/4 of the distance from A to B for A(2,5) and B(6,9)?

Answer 1

Answer:

p  is (3.71, 6.71)

Step-by-step explanation:

Given that p is at the distance of 3/4 from A to B

it mean that point p divides the line AB into 3:4 ratio.

and

if there are two points (x1,y1) and (x2,y22) which is divided by point p in the ratio m:n then

coordinates of point p (x,y) is given

p (x = (n*x1+m*x2)/m+n , y = (n*y1+m*y2)/m+n )

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Given the points AB

A(2,5)

B(6,9)

m:n = 3:4

thus,

p (x = (4*2+3*6)/7 , y = (4*5+3*9)/7 )

p (x = (4*2+3*6)/7 , y = (4*5+3*9)/7 )

p (x = (26/7 , y = 47/7 )

P ( x = 3.71, y = 6.71)

Thus, coordinates of point p  is (3.71, 6.71) which is  at  3/4 of the distance from A to B for A(2,5) and B(6,9)/