Answer:
9.01 maybe my math might be wrong
Step-by-step explanation:
where is the figure given?
Answer:
So possibilities of zeroes are:
Positive Negative Imaginary
1 1 2
3 1 0
Zeroes = -1.4549, 1.2658, 0.34457-1.0503i, 0.34457+1.0503i.
Step-by-step explanation:
Note: Descartes' Rule of Signs is used to find the signs of zeroes not the exact value.
The given function is
Degree of polynomial is 4 so number of zeroes is 4.
There are three sign changes, so there are either 3 positive zeros or 1 positive zero.
Now, put x=-x in f(x).
There is one variation in sign change, so there is 1 negative zero.
So possibilities of zeroes are:
Positive Negative Imaginary
1 1 2
3 1 0
Using graphing calculator the zeroes of given function are -1.4549, 1.2658, 0.34457-1.0503i and 0.34457+1.0503i.
Answer:
AB = 14 and BC = 17
Step-by-step explanation:
Congruence is a property that shows an equal relation between sides or angles of a given figure or two figures.
From the question, the given conditions are;
BC = AD, AD = 17, DC = 14, and m< 1 = m<2 .
i. Considering the property of congruence of sides,
BC = 17 (∵ BC = AD and AD has been given to equal 17)
i.e BC = AD = 17
ii. Considering the property of congruent angles and sides,
AB = 14 (∵ m<1 = m<2 and DC is 14)
Therefore, AB = 14 and BC = 17.
it has no solution, because the D is negative