Answer:
After 2 minutes the temperature of the hot chocolate will be 149.46 degrees Fahrenheit.
Step-by-step explanation:
We are going to use the Newton's law of cooling to solve this exercise. The Newton's law of cooling states that the amount of heat lost by a body is proportional to the difference of temperature between the body and the enviroment. We are going to use the following function :
T(t)=T_{0}+(T_{i}-T_{0}).e^{-kt}T(t)=T
0
+(T
i
−T
0
).e
−kt
Where ''T(t)'' is the temperature of the body that depends of the variable ''t'' which is time.
Where T_{0}T
0
is the temperature of the surroundings
In this case T_{0}T
0
is the temperature of the freezer
Where T_{i}T
i
is the initial temperature of the body which is cooling. In this case, T_{i}T
i
is the temperature of the hot chocolate
And where ''k'' is a constant. In this case, k=0.12k=0.12 is a data of the exercise
If we replace all the values in the equation and replacing t=2minutest=2minutes
⇒
T(2minutes)=0+(190-0).e^{-(0.12).(2)}T(2minutes)=0+(190−0).e
−(0.12).(2)
T(2minutes)=(190).(e^{-0.24})=149.46T(2minutes)=(190).(e
−0.24
)=149.46
We find that the temperature of the hot chocolate after 2 minutes is 149.46 degrees Fahrenheit
I believe that the answer is x=12.
It is exactly at the midpoint of the hypotenuse <span />
Answer:
2
Step-by-step explanation:
8x-1 = x+13
7x = 14
x = 2
Let x = the smaller angle
then 2x + 6 = the larger angle
Since they are comlementary, then their sum is 90°
smaller angle + larger angle = 90°
(x) + (2x+6) = 90
3x + 6 = 90
3x = 84
x = 28 (this is the smaller angle)
the larger angle is 2x + 6 = 2(28) + 6 = 56 + 6 = 62
