All categories

2 years ago

PLEASE HELP ME OVER HERE

Mathematics

2 answers:

uranmaximum [27]2 years ago

8 0

The proportion is the number of students in total/the amount of students who voted lasagna, you add all the votes together to get how many students there are in total (10+6+4=20) and 6 students voted for lasagna so the proportion would be 6/20 then you simplify it to 3/10 so the proportion of the students who like lasagna as their favorite pasta dish is 3/10

Artyom0805 [142]2 years ago

7 0

Answer:

Ummm what am i helping you with? You did not say anything, so i can't help you

Step-by-step explanation:

You might be interested in

- 3 + 3x = 2x – 13 I have to use more characters...

DENIUS [597]

- 3 + 3x = 2x – 13

Bring -3 to the right side of the equation by adding 3 to both sides

(- 3 + 3) + 3x = 2x – 13 + 3

0 + 3x = 2x - 10

3x = 2x - 10

Bring 2x to the other side by subtracting 2x to both sides

3x - 2x = 2x - 2x - 10

x = -10

Check:

-3 + 3(-10) = 2(-10) - 13

-3 + (-30) = -20 - 13

-33 = -33

Hope this helped!

~Just a girl in love with Shawn Mendes

6 0

2 years ago

Identify the slope as positive, negative, zero or undefined

slavikrds [6]

Answer:

Zero

Step-by-step explanation:

6 0

2 years ago

Bill Gates wrote a computer program that generates three random numbers

Allushta [10]

Answer:

1/1000

Step-by-step explanation:

The probability of two independent events A, B (independent = events that do not depend on each other) is given by the product of the individual probabilities of A and B:

$p(AB)=p(A)\cdot p(B)$ (1)

In this problem, the single event is "getting a 3" when extracting a random number between 1 and 10.

The total number of possible outcomes is

n = 10

While the number of succesfull outcomes (getting a 3) is only one:

$s=1$

So, the probability of drawing a 3 in 1 draw is

$p(3)=\frac{s}{n}=\frac{1}{10}$

Then, we want to find the probability of getting three "3" in 3 consecutive generations. These events are independent events, so we can use rule (1) to find the total probability, and we get:

$p(333)=p(3)p(3)p(3)=(\frac{1}{10})(\frac{1}{10})(\frac{1}{10})=\frac{1}{1000}$