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3 years ago

Richard got. 263, 148 hits when he did an internet search. What is the value of the digit 6 in this nunber?

Mathematics

2 answers:

dsp733 years ago

6 0

The place value of the number 6 is the ten thousands place.

Paul [167]3 years ago

3 0

Answer: The value of 6 is 60000.

Step-by-step explanation:

Since we have given that

263,148.

We need to find the value of the digit 6 in this number.

We first expand the above number :

$2\times 10^5+6\times 10^4+3\times 10^3+1\times 10^2+4\times 10^1+8\times 10^0$

So, 6 in the place of ten thousands.

And the value of 6 is 60000.

Hence, the value of 6 is 60000.

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damaskus [11]

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785 - 570 + 595 = 810

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4 years ago

Is the answer is b ? Help

PilotLPTM [1.2K]

Answer:

No, it is D.

Step-by-step explanation:

<em>It can not be A or C, because length can not be negative</em>

Because the y is the same, you only have to <em>count the distance of the x-axises</em>.

4 - (-3) is 7 units, which is D.

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3 years ago

Could someone help me rnnn?

GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola: $y=3x^2-4$

Step-by-step explanation:

Given:

y-intercept of parabola: -4
parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola: $y=a(x-h)^2+k$

(where (h, k) is the vertex and $a$ is some constant)

Substitute point (0, -4) into the equation:

$\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}$

Substitute point (-2, 8) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}$

Substitute point (1, -1) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}$

Equate to find h:

$\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}$

Substitute found value of h into one of the equations to find a:

$\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}$

Substitute found values of h and a to find k:

$\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}$

Therefore, the equation of the parabola in vertex form is:

$\implies y=3(x-0)^2-4=3x^2-4$

So the vertex of the parabola is (0, -4)

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