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weqwewe [10]
3 years ago
14

What why did you say you had $80.50 and you add that up

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
8 0

Answer:

im not sure i understand the question

Step-by-step explanation:

80.50 plus........plus what?

i am confusion

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Reason A pack of 140 stickers contains sheets of 28 stickers. Each
xxTIMURxx [149]

Answer:

you could divide

Step-by-step explanation:

4 0
3 years ago
Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

6 0
3 years ago
Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
Irina18 [472]

Answer:

x = 97.6

Step-by-step explanation:

cos = adjacent over hypotenuse

cos(55)=\frac{56}{x}

* multiply each side by x *

cos(55)*x=xcos(55)\\\frac{56}{x} *x=56\\56=xcos(55)

* divide each side by cos ( 55 ) *

\frac{xcos(55)}{cos(55)} =x\\\frac{56}{cos(55)} =97.63302055

we're left with x = 97.63302055

Our last step is to round to the nearest tenth of a foot

We get that x = 97.6

4 0
3 years ago
Two isosceles triangles share the same base. Prove that the medians to this base are collinear. (There are two cases in this pro
Anna71 [15]

Answer:

Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.

To prove: Point A,D,P are collinear.

Proof:

→Case 1.  When vertices A and P are opposite side of Base BC.

In Δ ABD and Δ ACD

AB= AC   [Given]

AD is common.

BD=DC  [median of a triangle divides the side in two equal parts]

Δ ABD ≅Δ ACD [SSS]

∠1=∠2 [CPCT].........................(1)

Similarly, Δ PBD ≅ Δ PCD [By SSS]

 ∠ 3 = ∠4 [CPCT].................(2)

But,  ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]

2 ∠2 + 2∠ 4=360° [using (1) and (2)]

∠2 + ∠ 4=180°

But ,∠2 and ∠ 4 forms a linear pair i.e Point D is common point of intersection of median AD and PD of ΔABC and ΔPBC respectively.

So, point A, D, P lies on a line.

CASE 2.

When ΔABC and ΔPBC lie on same side of Base BC.

In ΔPBD and ΔPCD

PB=PC[given]

PD is common.

BD =DC [Median of a triangle divides the side in two equal parts]

ΔPBD ≅ ΔPCD  [SSS]

∠PDB=∠PDC [CPCT]

Similarly, By proving ΔADB≅ΔADC we will get,  ∠ADB=∠ADC[CPCT]

As PD and AD are medians to same base BC of ΔPBC and ΔABC.

∴ P,A,D lie on a line i.e they are collinear.




3 0
3 years ago
Solving an Absolute Value Equation
Andre45 [30]

Answer:

Solution set = {-12, 12}

Step-by-step explanation:

Start by dividing both sides of the given equation by negative one, to get rid of the negative signs on both sides:

-\,|-x|=-\,12\\|-x|=12

Now we consider the two possible cases:

1) The expression inside the absolute value symbol is a positive number, then :

|-x|=-x\\

and replacing it in the equation, this becomes:

|-x|=12\\-x=12\\x=-12

which is our first answer.

2) The expression inside the absolute value symbol is a negative number, then :

|-x|=x\\

and replacing it in the equation, this becomes:

|-x|=12\\x=12

which is our second possible answer.

Then the set of solutions is: {-12, 12}

8 0
3 years ago
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