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kvv77 [185]
3 years ago
7

What is the vertex of g(x) = |x−2|+1 ?

Mathematics
2 answers:
Anit [1.1K]3 years ago
6 0

Answer:

(2, 1)

Step-by-step explanation:

The absolute value equation has the form f(x) = a |x-h|+k where (h, k) is the vertex.

Since this is g(x)=|x-2|+1 then the vertex is (2,1).

SashulF [63]3 years ago
5 0

Hello there,

What is the vertex of g(x) = |x−2|+1 ?

(-2, 1)

Answer: (2, 1)


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Burka [1]
One nice thing about this situation is that you’ve been given everything in the same base. To review a little on the laws of exponents, when you have two exponents with the same base being:

– Multiplied: Add their exponents
– Divided: Subtract their exponents

We can see that in both the numerator and denominator we have exponents *multiplied* together, and the product in the numerator is being *divided* by the product in the detonator, so that translates to *summing the exponents on the top and bottom and then finding their difference*. Let’s throw away the twos for a moment and just focus on the exponents. We have

[11/2 + (-7) + (-5)] - [3 + 1/2 + (-10)]

For convenience’s sake, I’m going to turn 11/2 into the mixed number 5 1/2. Summing the terms in the first brackets gives us

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And summing the terms in the second:

3 + 1/2 + (-10) = 3 1/2 + (-10) = -6 1/2

Putting those both into our first question gives us -6 1/2 - (-6 1/2), which is 0, since any number minus itself gives us 0.

Now we can bring the 2 back into the mix. The 0 we found is the exponent the 2 is being raised to, so our answer is

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3 years ago
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Answer:

Following are the solution to the given points:

Step-by-step explanation:

When the two-tailed were testing then:

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