Answer:
The correct answer is the linear model would be y = 500x - 390 where x is the number of swords sold in a month and y is the net monthly profit; B. 4.96 ≈ 5 swords monthly.
Step-by-step explanation:
Let x number of swords are sold per month.
Cost price of the swords per month is $ 195x.
Fixed cost to maintain the website per month is $390.
Total cost incurred per month is $ (195x + 390).
Selling price per katana is $695.
Total selling price of x swords per month is $695x.
Therefore, Net monthly profit y =695x - (195x + 390)
⇒ y = 695x - 195x - 390
⇒ y = 500x - 390
Thus the linear model would look like y = 500x - 390 where x is the number of swords sold in a month and y is the net monthly profit.
B. Now, given monthly profit y = $2090.
Thus the number of swords needed to be sold is
2090 = 500x - 390
⇒ 2480 = 500x
⇒ x = 4.96
A minimum of 5 swords need to be sold to get a monthly profit of more than $2090.
Answer:
13n
Step-by-step explanation:
Add them together. They are like terms.
Narrowing it down it's either a or c because the other 2 choices open downward (negative a).
Graphing the 2 parabolas choice c is narrower.
c
