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3 years ago

1 and 1 7th times 1 and 3 4th and writing the product in simplest form

Mathematics

2 answers:

BlackZzzverrR [31]3 years ago

8 0

Numerators: 8 and 7 = 56
Denominaters; 7 and 4 =28

Final answer 56/28 or 2

Jlenok [28]3 years ago

4 0

2 for a whole number and 56/28 as a fraction

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What is the product

Talja [164]

Answer:

6 12 2

0 0 0

0 6 2

Step-by-step explanation:

multiply each single number in each row with the number in the same row but across the multiplication symbol.

3 x 2 = 6

6 x 2 = 12

etc

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3 years ago

Which graph accurately indicates the region, shaded in green, that would determine the solution for the

andreyandreev [35.5K]

Answer is 3.14272833858583

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3 years ago

WHat is the answer to this?

frez [133]

Answer:

0.9

Step-by-step explanation:

First, convert them all into fractions:

$2\frac{1}{3}=\frac{7}{3}$

$.5=\frac{1}{2}$

Now, we have:

$\frac{4x+9}{\frac{7}{3} } =\frac{3x}{\frac{1}{2} }$

Cross multiply:

$\frac{1}{2} (4x+9)=\frac{7}{3} (3x)$

On the left, distribute. On the right, notice that the 3 in the denominator and the coefficient 3 cancel:

$2x+4.5=7x$

$4.5=5x$

$x=0.9=9/10$

4 0

3 years ago

Read 2 more answers

John watched television for 1 hour 35 minutes. Later he read. He watched television and read for a total of 3 hours 52 minutes.

liubo4ka [24]

Answer:

2hours and 17 minutes

Step-by-step explanation:

7 0

3 years ago

For a new customer, a video store charges $10 for a rental card plus $2 per movie. Using the linear equation (y=mx+b) you wrote,

netineya [11]

Given:

Charges for rental card = $10

Charges for movie = $2 per movie

To find:

The linear equation for given situation and find the cost to rent 6 movies.

Solution:

Let y be the total cost for x number of movies.

Cost of one movie = $2

Cost of x movies = $2x

Total cost = Charges for rental card + Charges for x movies

$y=10+2x$

Put x=6 to find the cost of 6 movies.

$y=10+2(6)$

$y=10+12$

$y=22$

Therefore, the total cost for a new customer to rent 6 movies is $22.

8 0

2 years ago