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lys-0071 [83]
3 years ago
11

Implement function easyCrypto() that takes as input a string and prints its encryption

Computers and Technology
1 answer:
jasenka [17]3 years ago
4 0

Answer:

The program written in python is as follows;

import string

def easyCrypto(inputstring):

      for i in range(len(inputstring)):

             try:

                    ind = string.ascii_lowercase.index(inputstring[i])

                    pos = ind+1

                    if pos%2 == 0:

                           print(string.ascii_lowercase[ind-1],end="")

                    else:

                           print(string.ascii_lowercase[ind+1],end="")

             except:

                    ind = string.ascii_uppercase.index(inputstring[i])

                    pos = ind+1

                    if pos%2 == 0:

                           print(string.ascii_uppercase[ind-1],end="")

                    else:

                           print(string.ascii_uppercase[ind+1],end="")

anystring = input("Enter a string: ")

easyCrypto(anystring)

Explanation:

The first line imports the string module into the program

import string

The functipn easyCrypto() starts here

def easyCrypto(inputstring):

This line iterates through each character in the input string

      for i in range(len(inputstring)):

The try except handles the error in the program

             try:

This line gets the index of the current character (lower case)

                    ind = string.ascii_lowercase.index(inputstring[i])

This line adds 1 to the index

                    pos = ind+1

This line checks if the character is at even position

                    if pos%2 == 0:

If yes, it returns the alphabet before it

                           print(string.ascii_lowercase[ind-1],end="")

                    else:

It returns the alphabet after it, if otherwise

                           print(string.ascii_lowercase[ind+1],end="")

The except block does the same thing as the try block, but it handles uppercase letters

<em>              except: </em>

<em>                     ind = string.ascii_uppercase.index(inputstring[i]) </em>

<em>                     pos = ind+1 </em>

<em>                     if pos%2 == 0: </em>

<em>                            print(string.ascii_uppercase[ind-1],end="") </em>

<em>                     else: </em>

<em>                            print(string.ascii_uppercase[ind+1],end="") </em>

<em />

The main starts here

This line prompts user for input

anystring = input("Enter a string: ")

This line calls the easyCrypto() function

easyCrypto(anystring)

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Answer:

public static int factorial(int n) {

   

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