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romanna [79]
3 years ago
15

A moose population is growing exponentially following the pattern in the table shown below. Assuming that the pattern continues,

what will be the population of moose after 12 years? Show all your work! Round your answer to the nearest whole number.
Mathematics
1 answer:
EleoNora [17]3 years ago
7 0

Answer:

  •   <u> 7,692 moose.</u>

Explanation:

The table that shows the pattern for this question is:

Time (year) Population

  0                   40

  1                     62

  2                    96

  3                   149

  4                   231

A growing exponentially pattern may be modeled by a function of the form P(x) = P₀(r)ˣ.

Where P₀ represents the initial population (year = 0), r represents the multiplicative growing rate, and P(x0 represents the population at the year x.

Thus you must find both P₀ and r.

<u>1) P₀ </u>

  Using the first term of the sequence (0, 40) you get:

   P(0) = 40 = P₀ (r)⁰ = P₀ (1) = P₀

Then, P₀ = 40

<u>  2) r</u>

Take two consecutive terms of the sequence:

  • P(0) = 40 r⁰ = 40
  • P(1) = 40 r¹ = 40r = 62
  • P(1) / P(0) = 40r / 40 = 62/40
  • r = 62/40 = 1.55

 

You can verify that, for any other two consecutive terms you get the same result: 96/62 ≈ 149/96 ≈ 231/149 ≈ 1.55

<u>3) Model</u>

 

Thus, your model is P(x) = 40(1.55)ˣ

<u> 4) Population of moose after 12 years</u>

  • P(12) = 40 (1.55)¹² ≈ 7,692.019 ≈ 7,692, which is round to the nearest whole number.
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Black_prince [1.1K]

Question is Incomplete;Complete question is given below;

Sam wants to fence his rectangular garden plot along its length on the front side. The perimeter of the plot is 24 meters, and its length is 3 times its width. If x is the length and y is the width of the plot, set the equations of the system. Solve and determine the values of x and y. If the cost of fencing is $25 per meter, how much does Sam need to spend on fencing?

Answer:

Length of the plot (x) is 9 meter and width of the plot (y) is 3 meter.

Sam need to spend $225 on fencing.

Step-by-step explanation:

Given;

Perimeter of the plot =24 m

Length of the plot is denoted 'x'

Width of the plot is denoted by 'y'

Cost of Fencing = $25 per meter.

We need to find the the values of x and y.

Also we need to find how much does Sam need to spend on fencing.

Solution:

Now given that;

length is 3 times its width.

so we get;

x=3y

Now we know that;

Perimeter of the rectangle is equal to 2 times sum of its length and width.

framing in equation form we get;

24=2(x+y)

But x=3y

so we get;

24 =2(3y+y)\\\\24=2(4y)\\\\24=8y

Dividing both side by 8 we get;

\frac{24}{8}=\frac{8y}{8}\\\\y =3\ m

Now width of the plot = 3 meter

Length of the plot x=3y=3\times3= 9\ m

Hence Length of the plot (x) is 9 meter and width of the plot (y) is 3 meter.

Now given that;

Sam wants to fence his rectangular garden plot along its length on the front side.

So we can say that;

Length to be fenced = 9 m

Cost of fencing = $25/meter

Cost of fencing the garden = 9\times 25= \$225

Hence Sam need to spend $225 on fencing.

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Answer:

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Step-by-step explanation:

5x-4y=10

-5x     +5x

-4y=10+5x

/-4     /-4

y=-2.5-5/4x

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3 years ago
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A sample of size n = 12 does not have a known population standard deviation. The population appears to be normally distributed.
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Given: Isosceles trapezoid EFGH
Andreyy89

Given: An Isosceles trapezoid EFGH in which EF =GH

To prove: ΔFHE ≅ ΔGEH

Proof: In Isosceles trapezoid EFGH, Considering two triangles ΔFHE and ΔGEH

  1. FE ≅ G H   → [ Given]

  2. ∠H = ∠E

→ Draw GM⊥HE and FN ⊥EH, and In Δ GMH and ΔFNE,

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∴ GM =FN [opposite sides of rectangle]

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→∠H =∠E [CPCT]

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→ΔFHE ≅ ΔGEH. [SAS]

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