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aksik [14]
3 years ago
11

50x+30y= 550 what is x and y

Mathematics
1 answer:
melomori [17]3 years ago
8 0

Answer:

<u>x = 8 and y = 5</u>

Step-by-step explanation:

The question is as following:

what is x and y for the following system of equations:

50x + 30 y = 550 ⇒ (1)

44x + 36 y = 532 ⇒ (2)

Subtract (1) - (2)

∴ 6x - 6y = 18

Divide both sides by 6

∴ x - y = 3

∴ x = 3 + y  ⇒ (3)

Substitute with the value of x at (1)

50(3+y) + 30y = 550

Solve for y

150 + 50y + 30y = 550

80y = 550 - 150 = 400

∴ y = 400/80 = 5

Substitute with the value of y at (3)

∴ x = 3 + y = 3 + 5 = 8

<u>So, x = 8 and y = 5</u>

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Answer

D. -3x + 4(2x-6) + 5

Step-by-step explanation:

-3x has nothing attached to it so leave it alone

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8x-3x=5x

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4 0
3 years ago
Read 2 more answers
The length of a picture is 15.75 inches shorter than twice the width. If the perimeter of the picture is 106.5 inches, find its
Vladimir79 [104]

Answer:

Length = 45.37 in

Width = 30.56 in

Step-by-step explanation:

Let the width of the picture be 'w' inches.

Given:

Perimeter of the picture is, P=106.5\ in

Length is 15.75 inches shorter than twice the width. So, length is:

l=2w-15.75

Now, we know that the perimeter of a rectangular shape is given as the sum of all of its side. So, the picture is also of rectangular shape and hence the perimeter is given as:

P=2l+2w

Plug in the values of 'l' and 'P' and solve for 'w'. This gives,

106.5=2w-15.75+2w\\106.5=4w-15.75\\106.5+15.75=4w\\4w=122.25\\w=\frac{122.25}{4}=30.56\ in

Therefore, the width of the rectangular picture is 30.56 inches.

Length of the picture is, l=2(30.56)-15.75=61.12-15.75=45.37\ in

So, length of the picture is 45.37 inches and width is 30.56 inches.

3 0
3 years ago
Find the volume.<br><br> Please help thank you!
faltersainse [42]
Hi there

2.5x2 = 5

length x width x height
3 0
3 years ago
Solve for s.<br><br> 3(s+8)=36<br><br><br> s = 2<br><br> s = 4<br><br> s = 8<br><br> s = 12
inysia [295]

Answer:

s=4

Step-by-step explanation:

divide by three =12 then -8 =4

4 0
2 years ago
Read 2 more answers
Write the direction cosines of the vector -21-5k​
AlekseyPX

Answer:

a=-2î+j-5k

|a| = √(−2)² +1² + (−5)²

a = √√4+1+25

a = √30

Thus, direction cosines of a are

(- 2/(sqrt(30)), 1/(sqrt(30)), - 5/(sqrt(30)))

6 0
3 years ago
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