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zalisa [80]
4 years ago
15

There are 18 female students and 16 male students in a class. Which of the

Mathematics
2 answers:
Digiron [165]4 years ago
8 0

Answer:

B

Step-by-step explanation:

The ratio

female : male = 18 : 16 ← simplify by dividing both parts by 2

18 : 16 = 9 : 8 ← in simplest form

dimaraw [331]4 years ago
3 0

The answer is 9 to 8

Hope this helps :)

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A cotton candy vendor has 22 cones of blue cotton candy to sell. If the blue cotton candy is 50% of the total number of cones, h
Feliz [49]
44. You can come to this answer by using algebra,
1/2x = 22
Multiply both sides by 2(denominator) thus,
X = 44.
Or you can use lateral thinking and realise that if 22 is 50%, you need to multiply by 2 to reach 100%.
4 0
4 years ago
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Armand deposited 389.42 in a savings account that earns 3.2% simple interest what is Amands account balance after seven years
Vinvika [58]
Account balance = $389.42   +   $389.42 (0.032) (7)

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3 years ago
En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand
Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} (1)

Donde:

F_{1} - Fuerza experimentada por el elefante, medida en newtons.

F_{2} - Fuerza aplicada sobre el plato pequeño, medida en newtons.

A_{1} - Área del plato grande, medida en metros cuadrados.

A_{2} - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g (2)

Donde:

D_{1} - Diámetro del plato grande, medido en centímetros.

D_{2} - Diámetro del plato pequeño, medido en centímetros.

m - Masa del elefante, medida en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que D_{1} = 0.75\,m, D_{2} = 0.13\,m, m = 2900\,kg y g = 9.807\,\frac{m}{s^{2}}, entonces la fuerza a aplicar al émbolo pequeño es:

F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F_{2} = 854.473\,N

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

3 0
3 years ago
Distributive property of 8 x 31
solong [7]
Your answer would be 248
7 0
3 years ago
A what is a letter or symbol that represents some unknown value
aleksley [76]
Unknown values can be taken as anything , for example : the most common is x for unknown values and sometimes, for angles we can take θ(theta).

it is totally upto you!
8 0
4 years ago
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