Tanyss's house has 25 windows. Her brother has washed 22 of the windows. What percent of the windows has her brother washed?

morpeh [17]

Step-by-step Explanation:

Part A: Algebraically write the equation of the best fit line in slope-intercept form. Include all of your calculations in your final answer.

Considering the data

Age (in years) Weight (in pounds)

2 32

6 47

7 51

4 40

5 43

3 38

8 60

1 23

Considering the slope intercept form

$y = mx + b$

where $m$ is the slope of the line and $b$ is the y-intercept.

Taking two points, lets say (2, 32) and (8, 60)

as

$\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(2,\:32\right),\:\left(x_2,\:y_2\right)=\left(8,\:60\right)$

$m=\frac{60-32}{8-2}$

$m=\frac{14}{3}$

so

$y = mx + b$

$\:\:32\:=\:\left(\frac{14}{3}\right)2\:+\:b$

$\mathrm{Switch\:sides}$

$\left(\frac{14}{3}\right)\cdot \:2+b=32$

$b=\frac{68}{3}$

Thus

$y = mx + b$

as

$m=\frac{14}{3}$ and $b=\frac{68}{3}$

substituting in the slop-intercept form

$y=\left(\frac{14}{3}\right)x+\left(\frac{68}{3}\right)$

Therefore, $y=\left(\frac{14}{3}\right)x+\left(\frac{68}{3}\right)$ is the equation of the best fit line in slope-intercept form.

Part B: Use the equation for the line of best fit to approximate the weight of the little girl at an age of 14 years old.

As the equation of line is

$y=\left(\frac{14}{3}\right)x+\left(\frac{68}{3}\right)$

So in order to find the weight of the little girl at an age of 14 years old, put

$x = 14$ in the above equation.

as

$y=\left(\frac{14}{3}\right)x+\left(\frac{68}{3}\right)$

$y=\left(\frac{14}{3}\right)\left(14\right)+\left(\frac{68}{3}\right)$ ∵ $x = 14$

$\:y=88$

Therefore, the approximate weight of the little girl at an age of 14 years old will be 88 pounds.

4 0

4 years ago

Hi if anyone could help that’d be amazing, tysm

andreyandreev [35.5K]

Answer:

I can't help you too much but for the first one its never repeat your ex

8 0

3 years ago

8) A school community had planned to reduce the number of grade 9 students per class room by constructing additional class rooms

Allisa [31]

Step-by-step explanation:

Let "c" be the original number of classrooms.

The 1200/c was the original number of students per classroom.

----

Equation:

1200/(c-4) = (1200/c)+10

Multiply thru by c(c-4)

---

1200c = 1200(c-4)+10c(c-4)

---

1200c = 1200c-4800 + 10c^2-40c

----

10c^2-40c-4800 = 0

c^2-4c-480 = 0

Factor:

(c-24)(c+20) = 0

---

Positive solution:

c = 24 (# of classrooms originaly planned)

7 0

3 years ago

HELPPPPP !!!!!!! Please answer correctly Will mark Brianliest !!!!!!!!!!

azamat

Sorry if I couldn’t help

5 0

3 years ago

Read 2 more answers

( please help, 20 points!! )

deff fn [24]

Measure of anfle 5=150

7 0

3 years ago