Ask question

Ask question

All categories

3 years ago

6

The 1997 value of an object was $9500. In 2012, it was worth $5000. The annual percent of decay has been constant. What is the a

nnual percent of decay?

1 answer:

Taya2010 [7]3 years ago

3 0

I don't know if this is right but I think it is $4500

You might be interested in

Please explain and I also need the answer ASAP... I need help with all of them haha...

Umnica [9.8K]

Answer:

I don't know how to help either I need the same answers as you pls

4 0

3 years ago

I need help trying to do this

GREYUIT [131]

Answer:

me likey points ❤️❤️❤️

5 0

2 years ago

Question: "If y > 3, what is the value of n ?"

iris [78.8K]

Answer:

y-3

Problem:

What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?

Step-by-step explanation:

Dividend=quotient×divisor+remainder

So we have

xy-3=(x-1)×(y)+remainder

xy-3=(xy-y)+remainder *distributive property

Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.

We need to get rid of minus y so we need plus y in the remainder.

We also need minus 3 in the remainder.

So the remainder is y-3.

Let's try it out:

xy-3=(xy-y)+remainder

xy-3=(xy-y)+(y-3)

xy-3=xy-3 is what we wanted so we are done here.

7 0

2 years ago

____ [38]

The answer is quadrant 2

7 0

3 years ago

Read 2 more answers

A sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to

Archy [21]

Answer:

0.2916, 0.1488, 0.0319

Step-by-step explanation:

Given that a sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to have oil added.

Since each trial is independent there is a constant probability for any random car to need oil is 0.10

Let X be the number of cars that need oil

A) Here X is BIN(4,0.1)

$P(X=1) = 4C1(0.1)(0.9)^3 \\= 0.2916$

B) Here X is Bin (8, 0.1)

$P(x=2) = 8C2 (0.1)^2 (0.9)^6\\\\=0.1488$

C) Here X is Bin (20,5)

$P(x=5) = 20C5 (0.1)^5 (0.9)^{15} \\=0.0319$

3 0

2 years ago