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Marianna [84]
3 years ago
10

Do yall know this ? (2)

Mathematics
1 answer:
Flauer [41]3 years ago
6 0
Nope we don’t know that
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Which is the slope of the line y=−3x+2?y=-3x+2?
Morgarella [4.7K]
The slope is -3.
Finding slope can be easy if you just remember that the formula is set up as y=mx+b.
The number in the 'm' place is always the slope.
Example: y=4x+1, the slope would be 4 because it's in the 'm' place.
If you have trouble remembering which place the slope is, trying thinking about skiing or sledding; you can only sled or ski down a Mountain slope. Mountain starts with M.
M=slope.
Hope this helps :)
If you have any questions, just let me know!
5 0
3 years ago
Plane AXS intersects with which planes? More than 1 answer.
Nata [24]

Answer:

Options A and Option B

Step-by-step explanation:

All four sides AX, IX, IS and AS of the base are common in the four side walls of the prism.

In other words, edge AX is common in planes AXU and AXS,

Edge XI is common in planes XIB and AXS,

Edge SI is common in planes EBS and AXS,

Edge AS is common in planes CEA and AXS.

Therefore, plane AXS is intersecting planes AXU and EBS.

Options A and Option B are the correct options.

8 0
3 years ago
All of them pls I am just helping my litte some think
IceJOKER [234]
Try to refrain from asking more than three questions per question for future reference. 

11+4=15
6+4=10
4+7=11
12+4=16
0+4=4
4+0=4
10+4=14
4+5=9
9+4=13
4+2=6
4+8=12
4+3=7
7+4=11
4+4=8
4+1=5
8+4=12

Hope this helps.
-Benjamin
5 0
3 years ago
Which equation has the correct sign on the product
dedylja [7]

Answer: B

Step-by-step explanation: 45 times (-6) =45 times 6 which equal 270

8 0
2 years ago
I need some help with this calculus question
Over [174]

The tangent to y at the point (0, 5) has a slope equal to the derivative evaluated at x=0.

y=x^4+5e^x\implies y'=4x^3+5e^x\implies y'(0)=5

This tangent passes through the point (0, 5), so its equation is

y-5=5(x-0)\implies y=5x+5

The normal line passes through the same point, but is perpendicular to the tangent line, so its slope is the negative reciprocal of the slope of the tangent. So the equation for the normal line is

y-5=-\dfrac15(x-0)\implies y=5-\dfrac x5

3 0
3 years ago
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