Do yall know this ? (2)

Andrew [12]

The greatest common factor is the biggest number taken from the values.

Q1. The answer is A. 5y^6

$20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}$
Since $x^{a}* x^{b} =x^{a+b}$ , then $x^{9}= x^{3}* x^{6}$

Back to our expression:
$4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+ 5y ^{6}*1=5 y^{6} (4y ^{3} +1)$
The greatest common factor is thus $5 y^{6}$

Q2. The answer is D. 12xy^2

$12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}$
We will use the rule $x^{a}* x^{b} =x^{a+b}$ to factorise the exponents:
$12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)$
The greatest common factor is thus $12xy^{2}$

3 0

3 years ago

Probability The average time between incoming calls at a switchboard is 3 minutes.if a call has just come in,the probability tha

Stels [109]

Answer:

a) 0.1535

b) 0.4866

c) 0.8111

Step-by-step explanation:

The probability that the next call come within the next t minutes is:

$p(t) = 1 -e ^{- t/3}$

According to this model,

a) the probability that a call in comes within 1/2 minutes is $p(t) = 1 -e ^{- (1/2)/3}$ =0.1535

b) the probability that a call in comes within 2 minutes is $p(t) = 1 -e ^{-2/3}$ =0.4866

c) the probability that a call in comes within 5 minutes is $p(t) = 1 -e ^{-5/3}$ =0.8111

6 0

3 years ago

Can someone help me please

IgorLugansk [536]

A) 4(25-3y)+5y=9
100-7y=9
   91=7y
   y=13
(-14,13)

b) 14-x=x-10
   2x=24
   x=12
(12,14)

c) 4x=12
  (3,7)

d) 18.5x+10.4y=200
   x+y=130

7 0

3 years ago

Calculate the difference between the two times. 8: 15 am. or pm 3: 30 am or pm.

Vlad1618 [11]

Answer:

5:15 pm is the answer for the question

8 0

3 years ago

Can someone please check this for me? distance formula

seropon [69]

-4,6) (8,-12)
square root of 12^2+-18^2
square root of 144+324
square root of 468
21.63

5 0

3 years ago

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