Let x,y be two different numbers
suppose x^2=y^2
then x^2-y^2=0
which yields (x+y)(x-y)=0
so either x=y or x=-y
In any case, x and y must be the same value
also when a vairable is squared like y=x^2
we must note that there are 2 possible solutions
x=(+/-)sqrt(y)
Answer:
1. 4(4-9m) 2. 8(x-5) 3. 7(5-3a) 4. 2(2n-1) 5. -10(3n+1) 6. 6(5n+1) 7. 10(3x+7) 8. -3(n+4) 9. 2(9-2a) 10. 8(1-k) 11. 5(8-7n) 12. 5(9x-5)
Step-by-step explanation:
Hello,
2ay²+5ay-3a=a(2y²+5y-3)
=a(2y²+6y-y-3)=a(2y(y+3)-(y+3))
=a(y+3)(2y-1)
Answer:
60WPM
Step-by-step explanation:
120/2 = 60
As we know assets = liabilities + equity
In this case assets would be increased by $76,000 and the liabilities would be increased by $76,000
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