Answer:
josiahs distance from the starting line at a time when shes behind josiah
Step-by-step explanation: got it right in khan
The general solution for the given equation is 40°+120°n.
The period of g(x) is π.
The range of f(x) is [-1, 1].
- sin(x-30°) = cos 2x
- sin(x-30°) = sin(90°-2x)
- (x-30°) = (90°-2x) + 360°n
- x + 2x = 90° + 30° + 360°n
- 3x = 120° + 360°n
- x = (120° + 360°n)/3
- The general solution (x) is 40° + 120°n.
- g(x) = cos 2x
- The period of cos x is 2π.
- If the multiplying factor of x is 'n', then it decreases the period by n times.
- Here, in g(x), n is 2.
- The period of g(x) is equal to half the period of cos x.
- The period of g(x) = 2π/2
- The period of g(x) is π.
- f(x) = sin(x-30°)
- "Sin" is a trigonometric function which has a range from -1 to 1.
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16x +23
-16 -16
X = 7....................
B.
When two lines intersect they form two pairs of opposite angles.
Vertical angles are always congruent, which means that they are equal.
so m<7 = m<8 or m<3y + 19 = m<5y-29
C. solve for y and measure <7 and <8
3y + 19 = 5y-29
5y - 3y = 19+29
2y = 48
y = 24
so
5y-29 = 5(24) - 29 = 91
3y + 19 = 3(24) + 19 = 91
so <7 = 180 - 91 = 89
<7 = <8 = 89
