Answer:
Maybe 74
Step-by-step explanation:
42+64=106
180-106=74
125-13 = 112
112/2 = 56
The answer is C. 56
<span>x^3 - 6x^2 + 13x - 10
We have been given the roots 2+i and 2, so two of the factors in the desired polynomial is
(x - 2) = 0
(x - 2 -i ) = 0
Let's create a third root by negating the sign of the imaginary component to create the complex conjugate of the known complex root.
(x - 2 + i) = 0
Now multiple (x - 2 - i) and (x - 2 + i)
(x - 2 - i)
(x - 2 + i)
x^2 - 2x - xi
-2x +4 +2i
xi -2i - (-1)
x^2 -4x +4 + 1
x^2 -4x + 5
And we've cancelled the imaginary term. Let's multiply this quadratic equation by the remaining factor.
x^2 -4x + 5
x - 2
x^3 - 4x^2 + 5x
-2x^2 +8x -10
= x^3 -6x^2 + 13x - 10
So the desired polynomial is x^3 - 6x^2 + 13x - 10</span>
Step-by-step explanation:
I think the first number is 2
Then 2 x 2 = 4 so there is a difference of 4 number
Then in between 6 and 14 there is a difference of 8 so 4 x 2 = 8
Then 16 so 8 x 2 = 16
So after 126 the number is 254
It has infinite solutions
