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aivan3 [116]
4 years ago
10

Which choice is equivalent to 4 square root 8

Mathematics
1 answer:
den301095 [7]4 years ago
7 0

Answer:

A

Step-by-step explanation:

............................ ....

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Geometry// question #8
MAVERICK [17]

Answer:

see explanation

Step-by-step explanation:

The translation rule

(x, y ) → (x + 3, y - 2 )

Means add 3 to the original x- coordinate and subtract 2 from the original y- coordinate, thus

A(- 4, 1 ) → A'(- 4 + 3, 1 - 2 ) → A'(- 1, - 1 )

B(1, 1 ) → B'(1 + 3, 1 - 2 ) → B'(4, - 1 )

C(1, - 2 ) → C'(1 + 3, - 2 - 2 ) → C'(4, - 4 )

D(- 4, - 2 ) → D'(- 4 + 3, - 2 - 2 ) → D'(- 1, - 4 )

4 0
4 years ago
Xavier bought a shirt that was on sale for 20% off the original price. He also used a coupon that gave him an extra 15% off the
just olya [345]
To find the sale price multiply the original cost by the sale percentage. (37x.2= 7.4) subtract this discount from the total (37-7.4= 29.6) this is your sale price. Now multiply this by the other percentage (29.6x.15= 4.44) (29.6-4.44= 25.16) $25.16 is your final answer
4 0
3 years ago
Help help help help ill like five y’all brian list or something just pls help
lesya692 [45]
Hi can someone help me for correcting my text
8 0
3 years ago
Read 2 more answers
A parabola has its focus at (1,2) and its directrix is y=-2. the equation of this parabola could be
Oksi-84 [34.3K]
<span>x^2/8 - x/4 + 1/8 = 0 A parabola is defined as the set of all points such that each point has the same distance from the focus and the directrix. Also the parabola's equation will be a quadratic equation of the form ax^2 + bx + c. So if we can determine 3 points on the parabola, we can use those points to calculate the desired equation. First, let's draw the shortest possible line from the focus to the directrix. The midpoint of that line will be a point on the desired parabola. Since the slope of the directrix is 0, the line will have the equation of x=1. This line segment will be from (1,2) to (1,-2) and the midpoint will be ((1+1)/2, (2 + -2)/2) = (2/2, 0/2) = (1,0). Now for the 2nd point, let's draw a line that's parallel to the directrix and passing through the focus. The equation of that line will be y=2. Any point on that line will have a distance of 4 from the directrix. So let's give it an x-coordinate value of (1+4) = 5. So another point for the parabola is (5,2). And finally, if we subtract 4 instead of adding 4 to the x coordinate, we can get a third point of 1-4 = -3. So that 3rd point is (-3,2). So we now have 3 points on the parabola. They are (1,0), (5,2), and (-3,2). Let's create some equations of the form ax^2 + bx + c = y and then substitute the known values into those equations. SO ax^2 + bx + c = y (1) a*1^2 + b*1 + c = 0 (2) a*5^2 + b*5 + c = 2 (3) a*(-3)^2 + b*(-3) + c = 2 Let's do the multiplication for those expressions. So (4) a + b + c = 0 (5) 25a + 5b + c = 2 (6) 9a - 3b + c = 2 Equations (5) and (6) above look interesting. Let's subtract (6) from (5). So 25a + 5b + c = 2 - 9a - 3b + c = 2 = 16a + 8b = 0 Now let's express a in terms of b. 16a + 8b = 0 16a = -8b a = -8b/16 (7) a = -b/2 Now let's substitute the value (-b/2) for a in expression (4) above. So a + b + c = 0 -b/2 + b + c = 0 And solve for c -b/2 + b + c = 0 b/2 + c = 0 (8) c = -b/2 So we know that a = -b/2 and c = -b/2. Let's substitute those values for a and c in equation (5) above and solve for b. 25a + 5b + c = 2 25(-b/2) + 5b - b/2 = 2 -25b/2 + 5b - b/2 = 2 2(-25b/2 + 5b - b/2) = 2*2 -25b + 10b - b = 4 -16b = 4 b = -4/16 b = -1/4 So we now know that b = -1/4. Using equations (7) and (8) above, let's calculate a and c. a = -b/2 = -(-1/4)/2 = 1/4 * 1/2 = 1/8 c = -b/2 = -(-1/4)/2 = 1/4 * 1/2 = 1/8 So both a and c are 1/8. So the equation for the parabola is x^2/8 - x/4 + 1/8 = 0 Let's test to make sure it works. First, let's use an x of 1. x^2/8 - x/4 + 1/8 = y 1^2/8 - 1/4 + 1/8 = y 1/8 - 1/4 + 1/8 = y 1/8 - 2/8 + 1/8 = y 0 = y And we get 0 as expected. Let's try x = 2 x^2/8 - x/4 + 1/8 = y 2^2/8 - 2/4 + 1/8 = y 4/8 - 1/2 + 1/8 = y 4/8 - 1/2 + 1/8 = y 1/2 - 1/2 + 1/8 = y 1/8 = y. Let's test if (2,1/8) is the same distance from both the focus and the directrix. The distance from the directrix is 1/8 - (-2) = 1/8 + 2 = 1/8 + 16/8 = 17/8 The distance from the focus is d = sqrt((2-1)^2 + (1/8-2)^2) d = sqrt(1^2 + -15/8^2) d = sqrt(1 + 225/64) d = sqrt(289/64) d = 17/8 And the distances match again. So we do have the correct equation of: x^2/8 - x/4 + 1/8 = 0</span>
4 0
4 years ago
Paul answer 2 out of 5 questions correctly Jan answered 43% of her questions correctly and Juan answered 13 correctly and 6 inco
nika2105 [10]
2/5 = 40%
43%
13/19 = 68.4%

Juan
7 0
4 years ago
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