1) X^5Y/X^5= X^0Y= Y (Anything raise to power of 0 is 1)
2)(3mn)^1= 3mn
3)m^-4xM^5= M^-4+5= M
4) 5^-4x5^4= 5^-4+4= 5^0= 1
5) nm^3/n^3m= n^1-3m^3-1= n^-2m^2= m^2/n^2
6) (-2)^0= 1
therefore number 4 and 6 has the value of 1
Answer:
Step-by-step explanation:
step 1
Find the slope of the perpendicular line
we know that
If two lines are perpendicular, then their slopes are opposite reciprocal
(the product of their slopes is equal to -1)
In this problem
we have
The equation of the given line is 
so
the slope of the perpendicular line to the given line is
step 2
Find the equation of the line in point slope form
we have
substitute
Convert to slope intercept form
Distribute right side
A) 8 + 7 + 5 = 20 parts
b) 220 kg ÷ 20 = 11
c) <span> 8 parts crushed gravel: 8 x 11 = 88 kg
7 parts water: 7 x 11 = 77 kg
5 parts cement: 5 x 11 = 55 kg</span>
Answer:
surface area of the smaller figure ≈ 1474.64 m²
Step-by-step explanation:
The figures are similar base on the question . The surface area and the volume of the larger figure is given while only the figure of the smaller figure is given.
To find the surface area of the smaller figure we simply use the ratios. That is the scale factors.
Therefore, they are similar figure the scale factor can be represented as a:b.
The scale factor for volume is cubed.
volume of larger figure/volume of the small figure = a³/b³
4536/2625 = a³/b³
a/b = 16.5535451/13.7946209
Note that for two similar solid with scale factor a:b the surface area ratio is a²: b² (the scale factor is square)
16.55²/13.79² = 2124/x
273.9025/190.1641 = 2124/x
cross multiply
273.9025x = 403908.54840
x = 403908.54840/273.9025
x = 1474.6435261
x ≈ 1474.64 m²
1 is the simplest form since the line means division. 54 divided by 54 is 1.
