What is the equation of a line that contains point (4, –3) and is PARALLEL to –4x + y = 7?
2 answers:
Answer:
(4,3),y=(7)/(4)x+1
Step-by-step explanation:
To find an equation that is parallel to y = 7 4 x + 1 y=74x+1, the slopes must be equal. Using the slope of the equation, find the parallel line using the point-slope formula. ( 4 , 3 ) (4,3) m = 7 4
Using the point-slope form y − y 1 = m ( x − x 1 ) y-y1=m(x-x1), plug in m = 7 4 m=74, x 1 = 4 x1=4, and y 1 = 3 y1=3. y − ( 3 ) = ( 7 4 ) ( x − ( 4 ) )
Solving for y:
Multiply − 1 -1 by 3 3. y − 3 = ( 7 4 ) ( x − ( 4 ) ) y-3=(74)(x-(4)) Simplify ( 7 4 ) ( x − ( 4 ) ) (74)(x-(4)).
y − 3 = 7 x 4 − 7
y = 7 x 4 − 4 y=7x4-4 Reorder terms. y = 7 4 x − 4
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Answer:
x = 14
m∠SOP = (7x - 2)° = 96°
m∠SOR = (5x + 14) = 84°
Step-by-step explanation:
`From the given picture,
Angle SOP and angle SOR are the linear pairs.
Therefore, sum of these angles will be equal to to 180°.
m∠SOP + m∠SOR = 180° -----(1)
Since, m∠SOP = (7x - 2)° and m∠SOR = (5x + 14)°
[There is a misprint in this question. There should be x in place of y in the measures of the angles]
By substituting these values in the equation (1),
(7x - 2) + (5x + 14) = 180
12x + 12 = 180
12x = 180 - 12
12x = 168
x =
x = 14
m∠SOP = (7x - 2)° = 96°
m∠SOR = (5x + 14) = 84°