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3 years ago

In a survey of music preference, 82 out of 450 student said that they preferred country music . What percent of the students pre

ferred country music ?

Mathematics

1 answer:

Ivanshal [37]3 years ago

5 0

$\frac{82}{450}\cdot100\%=\frac{164}{9}\%=18\frac{2}{9}\%$

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What is the domain of the function f(w) = 0.5(35 – 2w)? Explain your answer.

Igoryamba

The domain is all real numbers, the function is a variant of linear, which could be expressed in the form of y=mx+b as y = -w + 17.5, therefore all real numbers is the domain and the range.

5 0

3 years ago

-8u = -7u+ 5<br> U=<br> Help

Thepotemich [5.8K]

Answer:

U = -5

Step-by-step explanation:

-8u = -7u + 5

-u = 5

u = -5

3 0

3 years ago

Megan buys 3 bracelets and 3 necklaces each bracelet cost 5 dollars each in dollars of one she gave the clerk 40$

Tatiana [17]

Not sure what answer your needing so here is a breakdown of the amounts.

3 bracelets times $5 equals $15

How much is each necklace?

Subtract $15 from $40 you have $25 left. Then you divide $25 by 3 you get each necklace costs $8.33 so three necklaces cost $24.99

When you add $15 from the bracelets and $24.99 from the necklaces your total is $39.99 that’s why Megan gave the clerk $40

Hope this helps

7 0

3 years ago

Rationalise the denominator of:<br>1/(√3 + √5 - √2)

Paul [167]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm :\longmapsto\:\dfrac{1}{ \sqrt{3} + \sqrt{5} - \sqrt{2} }$

can be re-arranged as

$\rm :\longmapsto\:\dfrac{1}{ \sqrt{3} - \sqrt{2} + \sqrt{5} }$

$\rm \: = \: \dfrac{1}{( \sqrt{3} - \sqrt{2} ) + \sqrt{5} }$

On rationalizing the denominator, we get

$\rm \: = \: \dfrac{1}{( \sqrt{3} - \sqrt{2} ) + \sqrt{5} } \times \dfrac{( \sqrt{3} - \sqrt{2} ) - \sqrt{5} }{( \sqrt{3} - \sqrt{2} ) - \sqrt{5} }$

We know,

$\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) = {x}^{2} - {y}^{2} \: }}$

So, using this, we get

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{ {( \sqrt{3} - \sqrt{2} )}^{2} - {( \sqrt{5}) }^{2} }$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{3 + 2 - 2 \sqrt{6} - 5}$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{5 - 2 \sqrt{6} - 5}$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{ - 2 \sqrt{6}}$

$\rm \: = \: \dfrac{ - ( - \sqrt{3} + \sqrt{2} + \sqrt{5}) }{ - 2 \sqrt{6}}$

$\rm \: = \: \dfrac{- \sqrt{3} + \sqrt{2} + \sqrt{5}}{2 \sqrt{6}}$

On rationalizing the denominator, we get

$\rm \: = \: \dfrac{- \sqrt{3} + \sqrt{2} + \sqrt{5}}{2 \sqrt{6}} \times \dfrac{ \sqrt{6} }{ \sqrt{6} }$

$\rm \: = \: \dfrac{- \sqrt{18} + \sqrt{12} + \sqrt{30}}{2 \times 6}$

$\rm \: = \: \dfrac{- \sqrt{3 \times 3 \times 2} + \sqrt{2 \times 2 \times 3} + \sqrt{30}}{12}$

$\rm \: = \: \dfrac{- 3\sqrt{2} + 2 \sqrt{3} + \sqrt{30}}{12}$

Hence,

$\boxed{\tt{ \rm \dfrac{1}{ \sqrt{3} + \sqrt{5} - \sqrt{2} } =\dfrac{- \sqrt{3 \times 3 \times 2} + \sqrt{2 \times 2 \times 3} + \sqrt{30}}{12}}}$

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<h3><u>More Identities to </u><u>know:</u></h3>

$\purple{\boxed{\tt{ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}}}}$

$\purple{\boxed{\tt{ {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}}}}$

$\purple{\boxed{\tt{ {(x + y)}^{3} = {x}^{3} + 3xy(x + y) + {y}^{3}}}}$

$\purple{\boxed{\tt{ {(x - y)}^{3} = {x}^{3} - 3xy(x - y) - {y}^{3}}}}$

$\pink{\boxed{\tt{ {(x + y)}^{2} + {(x - y)}^{2} = 2( {x}^{2} + {y}^{2})}}}$

$\pink{\boxed{\tt{ {(x + y)}^{2} - {(x - y)}^{2} = 4xy}}}$

6 0

3 years ago

9)Rover the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall. The

Sidana [21]

The dog can roam 59.7 feet if the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall.

<h3>What is the Pythagoras theorem?</h3>

The square of the hypotenuse in a right-angled triangle is equal to the sum of the squares of the other two sides.

We have:

Rover the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall. The other end of the leash is tied to the top of an 8-foot pole.

After drawing a right-angle triangle from the above information.

Applying Pythagoras' theorem:

60² = 6² + x²

After solving:

x = 59.69 ≈ 59.7 foot

Thus, the dog can roam 59.7 feet if the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall.

Learn more about Pythagoras' theorem here:

brainly.com/question/21511305

#SPJ1

5 0

2 years ago