Answer:

Step-by-step explanation:
We are given the following in the question:
Manager's claim: The mean guest bill for a weekend is $600 or less.
A member of the hotel’s accounting staff noticed that the total charges for guest bills have been increasing in recent months.
A sample of weekend guest bills were collected to test the manager’s claim.
We design the null and alternate hypothesis in the following manner:

Conclusion when null hypothesis cannot be rejected:
When we fail to reject the null hypothesis and accept the null hypothesis, thus, we have enough evidence to support the manager's claim that the mean guest bill for a weekend is $600 or less.
Conclusion when null hypothesis can be rejected:
When the null hypothesis is rejected, we accept the alternate hypothesis.
Thus, there are not sufficient evidence to support the manager's claim that the mean guest bill for a weekend is $600 or less.
Answer:
Step-by-step explanation:
Answer:
off course D
Step-by-step explanation:
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Answer:
Probability p( selecting 8 cities alphabetically) = 2.48×10^-5
Step-by-step explanation:
Number of possible ways of choosing 8 cities=Permutation P(n,k) = n!/(n-k)!
P(8,8)= 8!/(8-8)! = 8! = 40,320
Probability (selecting 8 cities alphabetically) = 1/40320 = 2.48×10^-5