An 11-ft ladder leans against the side of a house. The bottom of the ladder is 9-ft from the side of the house. How high is the
top of the ladder from the ground? If necessary, round your answer to the nearest tenth
1 answer:
You might be interested in
Answer:
278.63 square inches
Step-by-step explanation:
Gina needs to cut two types of rectangles.
Dimensions of one rectangle is given as,
Width = 12 inches
Length = =
inches
So, the area of this rectangular paper will be
Area = width × length = = 171 inches²
Dimensions of the other rectangular paper has been given as
Width = =
inches
Length = =
inches
So, the area of this rectangle will be
Area = width × length = = 107.63 inches²
Thus the total area she need to cut = 171 + 107.63 = 278.63 square inches.
Each position in the sequence has 3 choices, and there are 5 positions, so we multiply 3 by itself 5 times:
Answer:
15 seconds
Step-by-step explanation:
If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy: the dog's rate is 150 and the squirrel's is 100. The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know: the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up. Since we don't know what d is, we will just call it d! Now it seems as though we have 2 unknowns which is a problem. However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other. Here's the dog's equation:
d = rt
d+200 = 150t
And the squirrel's:
d = 100t
If we solve both for t and set them equal to each other we have:
Now we can cross multiply to solve for d:
150d = 100d + 20,000 and
50d = 20,000
d = 400
But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took. So sub that d value back into one of the equations we have solved for t and do the math:
That's 1/4 of a minute which is 15 seconds.