1. What would s have to be so that x^3+ 5x^2 + sx + 6 is divisible by (x+2)?

Mathematics

1 answer:

777dan777 [17]3 years ago

8 0

Answer:

A. 9

Step-by-step explanation:

We use the remainder theorem.

The given function is

$f(x) = {x}^{3} + 5 {x}^{2} + sx + 6$

If this function is divisible by x+2, then by the remainder theorem,

$f( - 2) = 0$

This implies that;

${( - 2)}^{3} + 5( - 2 )^{2} + s( - 2) + 6 = 0$

We evaluate to get:

$- 8 + 20 - 2s + 6 = 0$

$18 - 2s = 0$

$2s = 18 \\ s = 9$

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Solve for n. n + 1 = 4(n - 8) n = 1 T n = 8 n = 11 n = 16

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Answer:

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