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4 years ago

Calculate the area of this parallelogram. LM=24cm PO=6cm

Mathematics

1 answer:

Sergio [31]4 years ago

4 0

Area is length times height

24 * 6 = 144

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If 2x-4(3-x)=18, then x=_____? Can someone please help me with this problem

denis-greek [22]

Answer:

Answer is below

Step-by-step explanation:

Simplify both sides of the equation.

$2x-4(3-x)=18\\2x+(-4)(3)+(-4)(-x)=18$

DIstribute

$2x+-12+4x=18\\(2x+4x)+(-12)=18$

CLT

$6x+-12=18\\6x-12=18$

Add 12 to both sides.

$6x-12+12=18+12\\6x=30$

Divide both sides by 6.

$\frac{6x}{6} =\frac{30}{6}\\ x=5$

7 0

3 years ago

Solve 3x1 = 12. Explain your reasoning.

Yuki888 [10]

The left side
3
3
does not equal to the right side
12
12
, which means that the given statement is false.
False

6 0

3 years ago

Read 2 more answers

A water storage tank is 4 m long, 3 m wide and 2 m deep. How many litres of water will it hold?

N76 [4]

Answer:

24 liters

Step-by-step explanation:

2×3×4

6 0

3 years ago

A circular target is divided into four rings that have equal areas. If the radius of the target is 24cm, find the radius of the

MAVERICK [17]

THE AREA OF THE RING WHICH IS INSIDE CIRCULAR TARGET IS 12CM.

Step-by-step explanation:

A circular target which is divided into four rings of equal areas as given in the information

The area of the circular target is

Area = $\pi$ * R².

As per the given data radius of the target 'R' is 24cm,

Area of circular target = $\pi$ * 24²

=> 576 $\pi$ .

let us consider radius of ring equals to 'r',

So, each of the ring has area of

=> Area of ring = ( $\pi$ * 576) / 4

=> 144 * $\pi$

Now let us consider area of the small ring inside circular target

Area of ring = $\pi$ * r²

$\pi$ * r² = 144 $\pi$

Taking off the $\pi$ from both sides

r² = 144

r = 12.

Therefore radius of ring which is inside circular target is 12 cm.

6 0

4 years ago

F(x) = -4x2 + 12x – 9

DochEvi [55]

Answer:

$D = 0$

The graph has 1 x-intercept

Step-by-step explanation:

Given

$f(x) = -4x^2 + 12x - 9$

Required

- Discriminant of f

- Number of x intercepts

Let D represent the discriminant;

D is calculated as thus

$D = b^2 - 4ac$

Where a, b and c are derived from the following general format;

$f(x) = ax^2 + bx +c$

By comparing $f(x) = ax^2 + bx +c$ with $f(x) = -4x^2 + 12x - 9$

We have

$f(x) = f(x)\\ax^2 = -4x^2\\bx = 12x\\c = -9$

Solving further;

$a = -4\\b=12\\c=-9$

So, D can now be calculated;

$D = b^2 - 4ac$ becomes

$D = 12^2 - 4 * -4 * -9$

$D = 144 - 144$

$D = 0$

Hence, the discriminant of f is 0

From the value of the discriminant, we can determine the number of x intercepts of the graph;

When D = 0, then; there exists only one x-intercept and it as calculated as thus

$x = \frac{-b}{2a}$

Recall that

$a = -4\\b=12\\c=-9$

So, $x = \frac{-b}{2a}$ becomes

$x = \frac{-12}{2 * -4}$

$x = \frac{-12}{-8}$

$x = \frac{12}{8}$

$x =1.5$

8 0

3 years ago