Answer:
Observe the attached image
Step-by-step explanation:
The limit of inequality is marked by the equation of the line
![y = \frac{1}{3}x +\frac{1}{2}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B3%7Dx%20%2B%5Cfrac%7B1%7D%7B2%7D)
Therefore the first step to graph the inequality is to graph the line
![y = \frac{1}{3}x +\frac{1}{2}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B3%7Dx%20%2B%5Cfrac%7B1%7D%7B2%7D)
First we find its cut point with the x axis. (y = 0)
![0 = \frac{1}{3}x +\frac{1}{2}](https://tex.z-dn.net/?f=0%20%3D%20%5Cfrac%7B1%7D%7B3%7Dx%20%2B%5Cfrac%7B1%7D%7B2%7D)
![-\frac{1}{2}= \frac{1}{3}x](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%3D%20%5Cfrac%7B1%7D%7B3%7Dx)
![x =\frac{-\frac{1}{2}}{\frac{1}{3}}\\\\x = -\frac{3}{2}](https://tex.z-dn.net/?f=x%20%3D%5Cfrac%7B-%5Cfrac%7B1%7D%7B2%7D%7D%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C%5C%5Cx%20%3D%20-%5Cfrac%7B3%7D%7B2%7D)
Second we find its cut point with the y axis. (x = 0)
![y= \frac{1}{3}(0) +\frac{1}{2}](https://tex.z-dn.net/?f=y%3D%20%5Cfrac%7B1%7D%7B3%7D%280%29%20%2B%5Cfrac%7B1%7D%7B2%7D)
![y =\frac{1}{2}](https://tex.z-dn.net/?f=y%20%3D%5Cfrac%7B1%7D%7B2%7D)
Now that we know the cut points, we can graph the line.
Then, the inequality
![y](https://tex.z-dn.net/?f=y%20%3C%5Cfrac%7B1%7D%7B3%7Dx%20%2B%5Cfrac%7B1%7D%7B2%7D)
it tells us that the region is made up of all the values of y that are smaller or that are below the equation of the line
.
In this way we shadow the region that is below the line and this will be the graph of the inequality. Observe the attached image
So it needs to be:
64/2=32
32/2=16
16/2=8
8/2=4
4/2=2
2/2=1
So there need to be 7 rounds.
Hope this helps :)
<span>2t^3-t-10=
+10 on both sides
2t^3-t=10
t^3=10
cube both sides by 3
t=1000</span>
Use f and m for "female" and "male." Then f = m + 16, and f + m = d (total)
So now we have the system of linear equations
f = m + 16
f + m = d
We can eliminate f by subst. m + 16 for f in the second equation:
d-16
m + 16 + m = d, or 2m + 16 = d. Find m. 2m = d - 16, so that m = --------
2
Assuming that the male horses are either brown or black, and that 25% of these are brown, then the rest must be black. This number is
d-16
0.75 [ --------- ] .
2
on the very far left it says (5,-1.5)