X2-2x-35=0x2-7x+5x-35=0x(x-7)+5(x-7)=0(x-7)(x+5)=0x-7=0 or x+5=0x=7 or x=-5 Check: x=7 ,LHS = 49-14-35 =0 =RHS x=-5, LHS = 25+10-35 =0=RHSAns: x=7 or x=-5
<span><span>x2</span>−x−12=0</span>
Answer:
x = 2 x = -6
Step-by-step explanation:
2 (x+2) ^2-4=28
Add 4 to each side
2 (x+2) ^2-4+4=28+4
2 (x+2) ^2= 32
Divide by 2
2/2 (x+2) ^2=32/2
(x+2)^2 = 16
Take the square root of each side
sqrt((x+2)^2) =±sqrt( 16)
x+2 = ±4
Subtract 2 from each side
x+2-2 = -2±4
x = -2±4
x = -2+4 and x = -2-4
x = 2 x = -6
The answer is -18. Hope this helps.
< W and < X are congruent....so they are equal.....so if their sum is 121....just divide by 2 for ur answer
121/2 = 60.5.....so < W = 60.5 and < X = 60.5
Answer:
(x - 5i)(x + 5i)
Step-by-step explanation:
Write this as x^2 + 25. Solving for x^2, we get x^2 = -25.
Recall that the square root of a negative number is an imaginary one. √(-25) equals ±5i (there are two roots, one positive and one negative).
Then x = ±5i.
In factored form, the given expression is (x - 5i)(x + 5i).
