If the equation is r = 3 +4cos(θ) then because b/a>1 the curve is a limacon with an inner loop.
Given limacon with equation r=3+4cos(θ) and we have to answer how the quotient of a and b relate to the existence of an inner loop.
Equation is like a relationship between two or more variables expressed in equal to form and it is solved to find the value of variables.
formula of polar graph is similar to r= a+ b cos (θ).
Case 1. If a<b or b/a>1
then the curve is a limacon with inner loop.
Case 2. If a>b or b/a<1
Then the limacon does not have an inner loop.
Here given that 
(θ)
It is observed that , a<b or b/a>1
Therefore the curve is limacon with an inner loop.
Hence because b/a>1 the curve is a limacon with an inner loop.
Learn more about limacon at brainly.com/question/14322218
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Answer:
Tyrone paid the higher markup rate.
Step-by-step explanation:
Tyrone and Terri both bought sofas with installment loans.
Tyrone bought his own with a sticker price of $1350 by paying $74 a month for 24 months. Therefore,
74 × 24 = $1776
The mark up = $1776 - $1350 = $426
Tyrone markup rate = 426/24 = $17.75 per month
Terri bought his own with sticker price of $950 by paying $52 a month for 24 months. Therefore,
52 × 24 = $1248
mark up = $1248 - $950 = $298
Terri markup rate = 298/24 = $12.4166666667 = $12.42 per month
Answer: The answer is 1/2 1/4 and 1/9
Step-by-step explanation: I did it already and i got it right
Step-by-step explanation:
the diameter of a circle is simply 2×radius.
2×15.4 = 30.8 m
the diameter is 30.8 m is true.
the circumference of a circle is
2×pi×radius
2×pi×15.4 = 30.8×pi m
the circumference is 30.8pi m is true.
therefore, the circumference can be found using
2(pi)(15.4)
is true.
now, doing the pi multiplication :
30.8 × pi = 96.76105373... m
the approximate circumference is 96.7 m is true.
6 diameters would be
30.8×6 = 184.8 m
that is much longer than the circumference.
so, more than 6 diameters could be wrapped around the circle is false, if we understand it that this is supposed to wrap the circle once without any overhanging remainder.
