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vodka [1.7K]
3 years ago
8

What is Copper (II) Oxide balanced

Chemistry
1 answer:
ikadub [295]3 years ago
5 0
Copper(II) oxide or cupric oxide is the inorganic compound with the formula CuO. A black solid, it is one of the two stable oxides of copper, the other being Cu2O or cuprous oxide. As a mineral, it is known as tenorite. It is a product of copper mining and the precursor to many other copper-containing products and chemical compounds
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Which sentences in the passage are true?
user100 [1]

Answer:

First and last sentence .‍♀️

Explanation:

An important thing to keep in mind about the Reading Comprehension section of the GRE as we use PowerPrep online to study is that it is just that—reading comprehension. In other words, as difficult as it may seem, and it can be pretty tricky, the test makers will always give us all the information we need in the passage to answer the question.

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4.) which organic compound has five carbon atom with at least one double bond?
victus00 [196]

Answer:

The answer is pentene.

Explanation:

The nomenclature for an organic compound with 5 carbon atoms will have a  -pent prefix.

An organic compound with at least one double bond will have alkene suffix, which is -ene.

Thus, the nomenclature for an organic compound that has 5 carbon atoms with at least one double bond will be pentene.  

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3 years ago
The subatomic particles found in the nucleus are
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C.) protons , the nucleus contains 2 subatomic particles , one protons & neutrons ( protons have a + charge & neutrons have no electrical charge
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To find the molecular formula from the empirical formula, one must determine the compounds _____
xxTIMURxx [149]

Answer:

Relative molecular of the compound or infomation like vapour density, volume occupied by a known mass of its vapour at stp, etc

Explanation:

The molecular mass of a compound is twice its vapour density. We can find the molecular formula using the relationship below:

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7 0
3 years ago
Sodium hydroxide reacts with aluminum and water to produce hydrogen gas:2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H2
Kay [80]

Answer: 0.147 grams

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al=\frac{1.33g}{27g/mol}=0.049moles

\text{Moles of} NaOH=\frac{4.25g}{40g/mol}=0.106moles

2Al(s)+2NaOH(aq)+6H_2O(l)\rightarrow Na(Al(OH)_4(aq)+3H_2(g)

According to stoichiometry :

2 moles of Al require = 2 moles of NaOH/tex]Thus 0.049 moles of [tex]Al will require=\frac{2}{2}\times 0.049=0.049moles  of NaOH

Thus Al is the limiting reagent as it limits the formation of product and NaOH is the excess reagent.

As 2 moles of Al give = 3 moles of H_2

Thus 0.049 moles of Al give =\frac{3}{2}\times 0.049=0.0735moles  of H_2

Mass of H_2=moles\times {\text {Molar mass}}=0.0735moles\times 2g/mol=0.147g

Thus 0.147 g of H_2 will be produced from the given masses of both reactants.

6 0
3 years ago
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