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tatuchka [14]
3 years ago
15

3.90x 10^22 He atoms express your answer using three significant figures

Chemistry
1 answer:
trasher [3.6K]3 years ago
3 0

Answer:

you have a scientific calculator us <u>it</u><em> </em><em>it's</em><em> </em><em>simple</em><em> </em>

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The density of the hydrocarbon in part (a) is 2.0 g l-1 at 50°c and 0.948atm. (i) calculate the molar mass of the hydrocarbon. (
Vedmedyk [2.9K]

1. Answer;

=56 g/mol

Explanation and solution;

PV = nRT

nRT= mass/molar mass (RT)

molar mass = (mass/V ) × (RT/P)

                   = Density × (RT/P)

Molar mass = 2.0 g/L × (0.0821 × 323 K)/0.948 atm

Molar mass = 56 g/mol


2. Answer;

Molecular mass is C4H8

Explanation;

Empirical mass × n = molar mass

Empirical mass for CH2 = 14 g/mol

Therefore;

56 g/mol = 14 g/mol × n

   n = 4

The molecular formula= 4(CH2)

    = C4H8


7 0
3 years ago
PLEASEEEE HELPPP I BEGGGG FOR HELPPP PLEASEE
belka [17]

Answer:

d

Explanation:

3 0
3 years ago
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A can of soda sitting on a supermarket shelf is a(n)
Maslowich
Isolated i believe dont hold me to that
8 0
3 years ago
A sample contains 16 mg of polonium-218. After 12 minutes, the sample will contain 1.0 mg of polonium-218. What is the half life
mariarad [96]

Answer:

Half-life = 3 minutes

Explanation:

Using the radioactive decay equation we can solve for reaction constant, k. And by using:

K = ln2 / Half-life

We can find half-life of polonium-218

Radioactive decay:

Ln[A] = -kt + ln [A]₀

Where:

[A] could be taken as mass of polonium after t time: 1.0mg

k is Reaction constant, our incognite

t are 12 min

[A]₀ initial amount of polonium-218: 16mg

Ln[A] = -kt + ln [A]₀

Ln[1.0mg] = -k*12min + ln [16mg]

-2.7726 = - k*12min

k = 0.231min⁻¹

Half-life = ln 2 / 0.231min⁻¹

<h3>Half-life = 3 minutes</h3>

5 0
3 years ago
Consider a balloon with volume V. It contains n moles of gas and has an internal pressure of P. The temperature of the gas is T.
Maksim231197 [3]

Answer:

V₂ = 0.6 V.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n is constant, and have different values of P, V and T:

<em>(P₁V₁T₂) = (P₂V₂T₁).</em>

<em></em>

V₁ = V, P₁ = P, T₁ = T.

V₂ = ??? V, ​P₂ = 1.25 P, T₂ = 0.75 T.

<em>∴ V₂ = (P₁V₁T₂)/(P₂T₁) =</em> (P)(V)(0.75 T)/(1.25 P)(T)<em> = 0.6 V.</em>

3 0
4 years ago
Read 2 more answers
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