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LUCKY_DIMON [66]
3 years ago
14

Na+ + Cl–  NaCl Which statement best describes the relationship between the substances in the equation?

Chemistry
2 answers:
hichkok12 [17]3 years ago
7 0
The correct answer for the question that is being presented above is this one: "The number of sodium ions is equal to the number of formula units of salt." The statement that best describes the relationship between the substances in the equation is that the number of sodium ions is equal to the number of formula units of salt.
ANTONII [103]3 years ago
3 0

Answer : The number of sodium ions is equal to the number of formula units of salt.


Explanation : In the given reaction of NaCl the statement which describes it the best is that the number of sodium ions is found to be same along with the formula units in the product side.


Na^{+} + Cl^{-} ----> NaCl.


Its clear from the equation that one mole of Na and one mole of Cl combines together to give the product, which is one mole of NaCl. The number of ions on both the sides are equal.

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What is the approximate frequency of a photon having an energy 3.2 * 10^-24 J? (h = 6.6*10^-34 J*s)
hichkok12 [17]

The Planck’s Equation states that

E = hv

E stands for energy measured in Joules

v stands for frequency measured in s^-1 or Hertz (Hz)- 1Hz .

h is Planck’s constant which is equivalent to 6.626x10-34 J.s


The Planck's equation states that the energy of a photon, is directly proportional to its frequency (v), by a constant factor (h).


Given:

E=3.2 * 10^-24 J

h= 6.626x10-34 J.s

Now we know that

E=hv

Thus substituting the given values we get

v=3.2 * 10^-24 /6.626x10-34

v=48 x 10^9 s^-1

4 0
3 years ago
What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?
mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

C=\frac{n}{V} .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is K_{2}SO_{4} thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass

Putting the values,

n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol

Thus, number of moles of  K_{2}SO_{4} will be 0.1061\times 0.5=0.053 mol.

The volume of solution is 225 mL, converting this into L,

1 mL=10^{-3}L

Thus,

225 mL=0.225 L

Putting the values in equation (1),

C=\frac{(0.053 mol}{0.225 L}=0.236 M

Therefore, concentration of potassium sulfate solution is 0.236 M.


4 0
3 years ago
9. Which of the following concentrations has units of moles of solute per liter of solution?
11Alexandr11 [23.1K]
The best answer for this is A) I’m pretty sure it is
7 0
3 years ago
When 3243. grams of iron (III) chloride are reacted with 511.8 grams of hydrosulfuric acid, which is the limiting reactant?
AleksAgata [21]

Answer:

Hydrosulfuric acid will act as limiting reactant.

Explanation:

Given data:

Mass of iron(III) chloride = 3243.0 g

Mass of hydrosulfuric acid = 511.8 g

Limiting reactant = ?

Solution:

Chemical equation:

2FeCl₃ + 3H₂S       →       Fe₂S₃ + 6HCl

Number of moles of iron(III) chloride:

Number of moles = mass/molar mass

Number of moles = 3243.0 g/ 162.2 g/mol

Number of moles = 20 mol

Number of moles of hydrosulfuric acid:

Number of moles = mass/molar mass

Number of moles = 511.8 g/ 34.1 g/mol

Number of moles = 15 mol

Now we will compare the moles of both reactant with products

                      FeCl₃          :          Fe₂S₃

                       2                :            1

                      20               :          1/2 ×20 = 10

                      FeCl₃          :            HCl

                       2                :              6

                      20               :          6/2 ×20 = 60

                      H₂S             :          Fe₂S₃

                       3                :            1

                      15               :          1/3 ×15 = 5

                      H₂S            :            HCl

                       3                :              6

                      15                :          6/3 ×15 = 30

Hydrosulfuric acid producing less number of moles of product thus, it will act as limiting reactant.

 

5 0
3 years ago
What is the mass in grams of 1.00*10^12 lead atoms
pav-90 [236]
34.5 X 10^-11 grams of lead
5 0
3 years ago
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