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Alex777 [14]
1 year ago
5

If you are examining a function over an interval ( a , b ) , for a and b finite, is it possible not to have an absolute maximum

or absolute minimum?
Mathematics
1 answer:
uysha [10]1 year ago
3 0

Yes, it is not possible to have an absolute maximum or absolute minimum.

Here,

We are examining a function over an interval ( a , b ) , for a and b finite,

We have to find,  is it possible not to have an absolute maximum or absolute minimum.

What theorem indicates the existence of absolute maxima or absolute minima of a function?

If f is continuous on a closed interval [a, b] (that is: on a closed and bounded interval), then, the Extreme Value Theorem indicates the existence of an absolute maximum or minimum value of f on the interval [a, b].

Now,

The function is define over an interval (a, b).

Hence, the function is define on open interval.

So, it is not possible to have an absolute maximum or absolute minimum.

Learn more about the existence of maxima and minima visit:

brainly.com/question/6787214

#SPJ4

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A survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the resul
pav-90 [236]

Answer:

95% confidence interval for the proportion of the adults who were opposed to the death penalty is (0.668, 0.704).

Step-by-step explanation:

We are given that a survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the results below, where X refers to the number of the respondents who were in favor.

X = 1,790

N = 2,610

\hat p = Sample proportion = X/N = 0.6858

Firstly, the pivotal quantity for 95% confidence interval for the population proportion  is given by;

     P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion = 0.6858

           n = sample of respondents = 2,610

           p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population​ proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at

                                   2.5% level of significance are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }]

  = [ 0.6858-1.96 \times {\sqrt{\frac{0.6858(1-0.6858)}{2610} } , 0.6858+1.96 \times {\sqrt{\frac{0.6858(1-0.6858)}{2610} } ]

  = [0.668 , 0.704]

Therefore, 95% confidence interval for the population proportion of the adults is (0.668, 0.704).

3 0
3 years ago
What dose 5h-2+9h equal explain☺
DerKrebs [107]
Start out by combining LIKE TERMS 
5h-2+9h 
in this case 9h and 5h are like terms so you would add both of those together.
9h+5h=14h
-2 has no like terms so we can't do anything with it our final answer would be:
14h-2
8 0
3 years ago
Giving 20 pts!!
kvasek [131]
Right ankle is exactly 90 degrees, while obtuse is more than, and acute is less than

4 0
3 years ago
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Tell which number is greater.<br><br> 1/3, 30%
Olin [163]
Mhm pretty sure 1/3
8 0
3 years ago
What is the domain of g
irakobra [83]

Answer:

We conclude that the set of numbers x satisfying -7 ≤ x ≤ 4 is an interval that contains -7, 4, and all numbers in between.

Thus, the domain of g is: -7 ≤ x ≤ 4

Step-by-step explanation:

We know that the domain of a function is the set of inputs or argument values for which the function is defined.

From the given graph, it is cleared that the function g starts from the x-value x = -7 and ends at x = 4.

It means the function is defined for the set of input values from x = -7 to x = 5 for which the function is defined.

Therefore, we conclude that the set of numbers x satisfying -7 ≤ x ≤ 4 is an interval that contains -7, 4, and all numbers in between.

Thus, the domain of g is: -7 ≤ x ≤ 4

4 0
3 years ago
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