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3 years ago

World Book is a/an A. Social media platform. B. Textbook. C. Almanac. D. Encyclopedia.

Computers and Technology

2 answers:

Nadusha1986 [10]3 years ago

8 0

D. Encyclopedia
Not a b or c

Lady_Fox [76]3 years ago

5 0

Answer:

Explanation:

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3 years ago

suppose you need to verify how to correctly use commas. you pen your English textbook and scan the chapter titles in which one w

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3 years ago

C - Language Write three statements to print the first three elements of array runTimes. Follow each statement with a newline. E

Jobisdone [24]

Answer:

Replace

/* Your solution goes here */

with

printf("%d",runTimes[0]);

printf("%d",runTimes[1]);

printf("%d",runTimes[2]);

Explanation:

The question requires that the first three elements of array runTimes be printed;

The first three elements are the elements at the first, second and third positions.

It should be noted the index of an array starts at 0;

So, the first element has 0 as its index

The second has 1 as its index

The third has 2 as its index

So, to make reference to the first three elements, we make use of

runTimes[0], runTimes[1] and runTimes[2] respectively

Having mention the above;

It should also be noted that array is of type integers;

So, to display integers in C, we make use of "%d";

Hence, the print statement for the first three elements is

printf("%d",runTimes[0]);

printf("%d",runTimes[1]);

printf("%d",runTimes[2]);

8 0

3 years ago

There are six different sequences for the three approval tasks: check inventory; check credit; check special terms.

Lana71 [14]

Answer:

i dont know i am 13

Explanation:

3 0

3 years ago

Write a function: function solution(N); that, given a positive integer N, prints the consecutive numbers from 1 to N, each on a

koban [17]

Answer:

The program written in Python is as follows:

def solution(N):

concat = ""

for i in range(1,N+1):

if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

print(str(i))

else:

if i%2 == 0:

concat= concat+"Codility"

if i%3 == 0:

concat= concat+"Testers"

if i%5 == 0:

concat= concat+"Coders"

print(concat)

concat = ""

N = int(input("Enter a positive integer: "))

solution(N)

Explanation:

This line declares the function

def solution(N):

This line initializes a variable named concat to an empty string

concat = ""

This line iterates from 1 to the input integer

for i in range(1,N+1):

This line checks if the current number of iteration is divisible by 2,3 or 5, if no, the number is printed

if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

print(str(i))

If otherwise

else:

This lines checks if current number is divisible by 2; if yes the string "Codility" is concatenated to string concat

if i%2 == 0:

concat= concat+"Codility"

This lines checks if current number is divisible by 3; if yes the string "Testers" is concatenated to string concat

if i%3 == 0:

concat= concat+"Testers"

This lines checks if current number is divisible by 2; if yes the string "Coders" is concatenated to string concat

if i%5 == 0:

concat= concat+"Coders"

The concatenated string is printed using this line

print(concat)

This variable concat is intialized back to an empty string

concat = ""

The main method starts here

N = int(input("Enter a positive integer: "))

This line calls the defined function solution

solution(N)

6 0

3 years ago