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Black_prince [1.1K]
3 years ago
7

World Book is a/an A. Social media platform. B. Textbook. C. Almanac. D. Encyclopedia.

Computers and Technology
2 answers:
Nadusha1986 [10]3 years ago
8 0
D. Encyclopedia
Not a b or c
Lady_Fox [76]3 years ago
5 0

Answer:

d

Explanation:

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suppose you need to verify how to correctly use commas. you pen your English textbook and scan the chapter titles in which one w
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C - Language Write three statements to print the first three elements of array runTimes. Follow each statement with a newline. E
Jobisdone [24]

Answer:

Replace

/* Your solution goes here */

with

printf("%d",runTimes[0]);

printf("%d",runTimes[1]);

printf("%d",runTimes[2]);

Explanation:

The question requires that the first three elements of array runTimes be printed;

The first three elements are the elements at the first, second and third positions.

It should be noted the index of an array starts at 0;

  • So, the first element has 0 as its index
  • The second has 1 as its index
  • The third has 2 as its index

So, to make reference to the first three elements, we make use of

<em>runTimes[0], runTimes[1] and runTimes[2]</em> respectively

Having mention the above;

It should also be noted that array is of type integers;

So, to display integers in C, we make use of "%d";

Hence, the print statement for the first three elements is

printf("%d",runTimes[0]);

printf("%d",runTimes[1]);

printf("%d",runTimes[2]);

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3 years ago
There are six different sequences for the three approval tasks: check inventory; check credit; check special terms.
Lana71 [14]

Answer:

i dont know i am 13

Explanation:

3 0
3 years ago
Write a function: function solution(N); that, given a positive integer N, prints the consecutive numbers from 1 to N, each on a
koban [17]

Answer:

<em>The program written in Python is as follows:</em>

def solution(N):

     concat = ""

     for i in range(1,N+1):

           if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

                 print(str(i))

           else:

                 if i%2 == 0:

                       concat= concat+"Codility"

                 if i%3 == 0:

                       concat= concat+"Testers"

                 if i%5 == 0:

                       concat= concat+"Coders"

                 print(concat)

                 concat = ""

N = int(input("Enter a positive integer: "))

solution(N)

Explanation:

This line declares the function

def solution(N):

This line initializes a variable named concat to an empty string

     concat = ""

This line iterates from 1 to the input integer

     for i in range(1,N+1):

<em>This line checks if the current number of iteration is divisible by 2,3 or 5, if no, the number is printed</em>

           if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

                 print(str(i))

<em>If otherwise</em>

           else:

<em>This lines checks if current number is divisible by 2; if yes the string "Codility" is concatenated to string concat</em>

                 if i%2 == 0:

                       concat= concat+"Codility"

<em>This lines checks if current number is divisible by 3; if yes the string "Testers" is concatenated to string concat</em>

<em>                 </em> if i%3 == 0:

                       concat= concat+"Testers"

<em>This lines checks if current number is divisible by 2; if yes the string "Coders" is concatenated to string concat</em>

                 if i%5 == 0:

                       concat= concat+"Coders"

<em>The concatenated string is printed using this line</em>

                 print(concat)

This variable concat is intialized back to an empty string

                 concat = ""

The main method starts here

N = int(input("Enter a positive integer: "))

This line calls the defined function solution

solution(N)

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