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sesenic [268]
4 years ago
13

For Adults/Adolescents, you should call/activate EMS: Before providing CPR. After providing CPR for 2 minutes. After an AED has

been administered. Or, none of the above.
Computers and Technology
1 answer:
defon4 years ago
6 0

Answer:

Before providing CPR is the correct option.

Explanation:

CPR refers to the cardiopulmonary resuscitation in which the user follows the emergency treatment of respiration from mouth to mouth and chest compression. If any person complete training of Adults/Adolescents then they have to activate or call the EMS before providing cardiopulmonary resuscitation.

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Which is the shortest and simplest tax form? <br> 1040 long form <br> 1040EZ<br> 1040A<br> 140E
Kay [80]
The answer is 1040EZ. That is the shortest and simplest tax form. 
7 0
3 years ago
Read 2 more answers
Write a program with 2 separate functions which compute the GCD (Greatest Common Denominator) and the LCM (Lowest Common Multipl
Maru [420]

Answer:

The program written in Python is as follows

def GCD(num1, num2):

    small = num1

    if num1 > num2:

         small = num2

    for i in range(1, small+1):

         if((num1 % i == 0) and (num2 % i == 0)):

              gcd = i

    print("The GCD is "+ str(gcd))

def LCM(num1,num2):

    big = num2  

    if num1 > num2:

         big = num1

    while(True):

         if((big % num1 == 0) and (big % num2 == 0)):

              lcm = big

              break

         big = big+1

     print("The LCM is "+ str(lcm))

 print("Enter two numbers: ")

num1 = int(input(": "))

num2 = int(input(": "))

GCD(num1, num2)

LCM(num1, num2)

Explanation:

This line defines the GCD function

def GCD(num1, num2):

This line initializes variable small to num1

    small = num1

This line checks if num2 is less than num1, if yes: num2 is assigned to variable small

<em>     if num1 > num2: </em>

<em>          small = num2 </em>

The following iteration determines the GCD of num1 and num2

<em>     for i in range(1, small+1): </em>

<em>          if((num1 % i == 0) and (num2 % i == 0)): </em>

<em>               gcd = i </em>

This line prints the GCD

    print("The GCD is "+ str(gcd))

   

This line defines the LCM function

def LCM(num1,num2):

This line initializes variable big to num2

    big = num2  

This line checks if num1 is greater than num2, if yes: num1 is assigned to variable big

<em>     if num1 > num2: </em>

<em>          big = num1 </em>

The following iteration continues while the LCM has not been gotten.

    while(True):

This if statement determines the LCM using modulo operator

<em>          if((big % num1 == 0) and (big % num2 == 0)): </em>

<em>               lcm = big </em>

<em>               break </em>

<em>          big = big+1 </em>

This line prints the LCM of the two numbers

     print("The LCM is "+ str(lcm))

The main starts here

This line prompts user for two numbers

print("Enter two numbers: ")

The next two lines get user inputs

num1 = int(input(": "))

num2 = int(input(": "))

This calls the GCD function

GCD(num1, num2)

This calls the LCM function

LCM(num1, num2)

<em></em>

<em>See attachment for more structured program</em>

Download txt
5 0
3 years ago
"Hubs:
Butoxors [25]

Answer:

Hubs incorporate amplifiers and repeaters.

Explanation:

Hub is an outdated way of connecting ethernet devices, they incorporate amplifiers and repeaters, they do not allow simultaneous communication among connected devices.

The latest technology in connecting ethernet devices are with the use of switch.

7 0
3 years ago
g Create a package named lab7 (no spaces, ALL in lowercase) where you will place your lab files. Write a class FilterWith with a
sweet [91]

Answer:

See explaination

Explanation:

import java.util.ArrayList;

import java.util.Scanner;

public class ListFilter

{

public static void filterRange(ArrayList<Integer> list,int min, int max)

{

ArrayList<Integer> listNew=new ArrayList<Integer>();

for(int i=0;i<list.size();i++)

{

if(list.get(i)>=min && list.get(i)<=max) //Checking if element is between min and max

{

listNew.add(list.get(i));

}

}

list.removeAll(listNew); //removing all elements from list.

}

public static void main(String[] args)

{

ArrayList<Integer> list=new ArrayList<Integer>();

list.add(4);

list.add(7);

list.add(9);

list.add(2);

list.add(7);

list.add(7);

list.add(5);

list.add(3);

list.add(5);

list.add(1);

list.add(7);

list.add(8);

list.add(6);

list.add(7);

Scanner sc=new Scanner(System.in);

System.out.println("Enter min : ");

int min=sc.nextInt();

System.out.println("Enter Max : ");

int max= sc.nextInt();

filterRange(list, min, max);

//Displaying new List

for(int i=0;i<list.size();i++)

{

System.out.print(list.get(i)+" ");

}

}

}

3 0
3 years ago
a. Write a function called fizzbuzz. This function will take 1 number as a parameter. The function will print all numbers from 0
OLga [1]

Answer:

def fizzbuzz (num):

 for item in range(num):

   if item % 2 == 0 and item % 3 == 0:

     print("fizzbuzz")

   elif item % 3 == 0:

     print("buzz")

   elif item % 2 == 0:

     print("fizz")  

   else:

     print (item)

fizzbuzz(20)

Explanation:

Using Python programming Language

Use a for  loop to iterate from 0 up to the number using the range function

Within the for loop use the modulo (%) operator to determine divisibility by 2 and 3 and print the required output

see attached program output screen.

5 0
3 years ago
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