Simplify the expression (a^2b^5c^3)^4(a^3b^3)^3(a^2c)^2

2 answers:

5 0

The simplified expression is shown below:

$( a^{2} b^{5} c^{3} )^{4} ( a^{3} b^{3} )^{3} ( a^{2} c )^{2} \\ \\ 
=( a^{8} b^{20} c^{12} )( a^{9} b^{9} )( a^{4} c^{2} ) \\ \\ 
= a^{(8+9+4)} b^{(20+9)} c^{(12+2)} \\ \\ 
= a^{21} b^{29} c^{14}$

zhenek [66]3 years ago

4 0

i think that's the answer a^21b^29c^14

You might be interested in

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago

PLZ HELP BRAINLIEST!!

kogti [31]

Answer:The accompanying table shows the number of trials and the ... Write the exponential regression equation for this set of data, rounding all values to no decimal places. Using this equation, find the value of her stock, to the nearest dollar, 10 years ... culture over a 5-hour period, where x is the time, in hours, and y is the number.

mark me brinlest plzz

Step-by-step explanation:

7 0

2 years ago

Exercise I: Fruit ninja 1. Determine the surface S given by the equation x 2 − 4x + y 2 − 2y + z 2 − 6z = 2. 2. Find an equation

nalin [4]

Answer:

Step-by-step explanation:

Detailed solution on the attached pictures