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diamong [38]
3 years ago
15

Write an equation for a line that is parallel to the graph of y = -3x + 6 and passes through the point at (-4, 7)

Mathematics
1 answer:
ale4655 [162]3 years ago
4 0
Y = -3x + 6....the slope here is -3. A parallel line will have the same slope.

y = mx + b
slope(m) = -3
(-4,7)....x = -4 and y = 7
now we sub into the formula and find b, the y int
7 = -3(-4) + b
7 = 12 + b
7 - 12 = b
-5 = b
so ur parallel equation is : y = -3x - 5 <==
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Answer:

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DiKsa [7]
The correct answer is:  [C]:  " (0, 24) " .
___________________________________________________________

Explanation:
___________________________________________________________

Given the quadratic function:
___________________________________________________________

          →  "  y = (x <span>− 8) (x + 3) "  ;   </span>←  Note:  Replace the "f(x)" with: "y" ; 

→  Find the "y-intercept".
___________________________________________________________

→  Note:  The "y-intercept" is the coordinate of the point(s) of the graph of the equation at which the graph crosses the "x-axis" when "x = 0" . 

   → So;  we set plug in "0" for "x" into our equation; and solve for "y" ; 

          → " y = (x − 8) (x + 3) " ;

          →   y = (0 − 8) (0 + 3)  ; 

          →   y = (-8) * (3)  ;  
 
          →   y = - 24 ; 
___________________________________________________________

So, the "y -intercept" of the <em><u>given</u></em> quadratic function is:
 
the point at which:  "x = 0 ; y = -24 " ;

      →  that is; the point  the coordinates:  " (0, - 24) " ;
___________________________________________________________
  →  which is:  Answer choice:  [C]:  " (0, - 24) " .
___________________________________________________________
9 0
3 years ago
Read 2 more answers
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dsp73

Answer:

A. 80-5x

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Option A is the correct option.

3 0
3 years ago
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