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uranmaximum [27]
3 years ago
6

Problem Solving

Mathematics
1 answer:
OlgaM077 [116]3 years ago
6 0

Answer:

168 shirts

Step-by-step explanation:

7*24=168

7=boxes

24=shirts per box

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I need help finding the missing sides
Greeley [361]

Answer:

12

Step-by-step explanation:

15/5 = 3

4*3 = 12

d = 12

the hypotenuse is 5^{2} + 4^{2} = c^{2}

25+16 = c^{2}

41=c^{2}

\sqrt{41}

8 0
3 years ago
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Can someone give me answers?
Alenkasestr [34]

Answer:

Maybe if you give a better quality photo that isn't sideways! :D

Step-by-step explanation:

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Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

V_{flask}=V_{sphere}+V_{cylinder}.

Use following formulas to determine volumes of sphere and cylinder:

V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

  • V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;
  • V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;
  • V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.

Then

\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.

Answer 2: correct choice is D.


8 0
4 years ago
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I need helpppppppppppp
ratelena [41]
The answer to question 3 is D. 15(4a+3). And the answer to question 4 is A. 90. Have a great day
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Corresponding angles of ΔABC and ΔDEF are congruent. Does this prove that the triangles are congruent?
Anit [1.1K]
The answer is letter D.
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