Given:
The right triangular prism.
Height of prism = 28 in.
Hypotenuse of base = 25 in.
leg of base = 24 in.
To find:
The lateral surface area of the prism.
Solution:
Pythagoras theorem:
Using Pythagoras theorem in the base triangle, we get
The perimeter of the triangular base is:
Lateral area of a triangular prism is:
Where, P is the perimeter of the triangular base and h is the height of the prism.
Putting 
in the above formula, we get
Therefore, the lateral area of the prism is 1568 in².
For the equation y - x < 0,
y < x
The shaded portion will be under the dashed line joining points (-2, -2) and (3, 3).
for the equation x - 1 > 0,
x > 1
The shaded portion will be to the right of the dashed line joining points (1, 5) and (1, -3).
The portion affected by the two shadings will be the portion common to the right of the dashed line joining points (1, 5) and (1, -3) and under the dashed line joining points (-2, -2) and (3, 3).
Therefore the correct answer is option c.
We have 55% and 80% antifreeze. We need 90 gallons of 75%.
F - 55% and E - 80%
A) F + E = 90
B) .55 F + .80 E = 67.50 (which is .75 * 90) Multiplying A) by -.55
A) -.55 F -.55 E = -49.50 (which is -.55 * 90) then adding A) & B)
.25 E = 18
E = 72 gallons of 80% and
F = 18 gallons of 55%
********* DOUBLE CHECK ******************
72 * .80 = 57.60 and 18 * .55 = 9.90
57.60 + 9.90 = 67.50 gallons of antifreeze and we have 90 total gallons
(67.50 / 90) * 100 = 75% correct!
Source: 1728.com/mixture.htm
Answer:
Y= -2x - 18
Step-by-step explanation:
Hope it works
