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3 years ago

Please explain your answer.

Mathematics

1 answer:

Vikki [24]3 years ago

8 0

Try this suggested explanation (see the attachment).

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Factor the gcf out of the polynomial 9x^6+6x^4+15x^3

san4es73 [151]

Answer:3x^3(3x^3+2x+5)

Step-by-step explanation:by looking at the polynomial, you can see that all three shares the variable x. Since 9,6, and 25 all share the GCF of 3, you can factor it out. Since the smallest x value of the polynomial is x^3, that is the x value you want to factor out. Since if you factor out x^3 then 15x^3 would not have a variable anymore.

4 0

4 years ago

What is the missing number in the ratio table? 5 15 7 9 27 11 33 13 39

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

the numbers are multiplying by 3

7 0

3 years ago

Evaluate the series 72+12+2+

RUDIKE [14]

72+12=84
84+2=86
So add 72 plus 12 and you get Eighty-Four . Plus 2 equals 86

3 0

3 years ago

On #10 i need help to solve this. please and thank you.

valina [46]

10a. $f(x) = x - 4$
 $h(x) = \sqrt{x - 5}$
 $(f - h)(6) = (6 - 4) - (\sqrt{6 - 5})$
 $(f - h)(6) = 2 - \sqrt{1}$
 $(f - h)(6) = 2 - 1$
 $(f - h)(6) = 1$

10b. $f(x) = x - 4$
 $g(x) = \frac{1}{x - 3}$
 $(f * g)(x) = (x - 4)(\frac{1}{x - 3})$
 $(f * g)(x) = \frac{x - 4}{x - 3}$
 Domain: (-∞, 3) ∨ (3, ∞) {x|x ≠ 3}
 Interval Notation: (3 < x < 3), (3 > x > 3)

10c. $g(x) = \frac{1}{x - 3}$
 $h(x) = \sqrt{x - 5}$
 $(g * h)(x) = (\frac{1}{x - 3})(\sqrt{x - 5})$
 $(g * h)(x) = \frac{\sqrt{x - 5}}{x - 3}$

10d. $f(x) = x - 4$
 $g(x) = \frac{1}{x - 3}$
 $h(x) = \sqrt[3]{x - 7}$
 $h(x) = (f * g)(x)$
 $\sqrt[3]{x - 7} = (x - 4)(\frac{1}{x - 3})$
 $\sqrt[3]{x - 7} = \frac{x - 4}{x - 3}$
 $(\sqrt[3]{x - 7})^{3} = (\frac{x - 4}{x - 3})^{3}$
 $x - 7 = \frac{(x - 4)^{3}}{(x - 3)^{3}}$
 $(x - 3)^{3}(x - 7) = (x - 4)^{3}$
 $(x^{3} - 9x^2 + 27x + 27)(x - 7) = (x^{3} - 12x^{2} + 48x - 64)$
 $x^{4} - 16x^{3} + 90x^{2} - 216x + 189 = x^{3} - 12x^{2} + 48x - 64$
 $x^{4} + 90x^{2} - 216x + 189 = 17x^{3} - 12x^{2} + 48x - 64$
 $x^{4} + 102x^{2} - 216x + 189 = 17x^{3} + 48x - 64$
 $x^{4} + 102x^{2} + 189 = 17x^{3} + 264x - 64$
 $x^{4} + 102x^{2} + 253 = 17x^{3} + 264x$
 $x^{4} - 17x^{3} + 102x^{2} - 264x + 253 = 0$
 $x = 4\ or\ 8$

4 0

3 years ago

(-4)(-1)(-2)(-6)(-3)(-5)(-2)(-2

STatiana [176]

First you get (-4)(-1)=4 cause the negatives cancel. Then you take 4(-2)=-8 Then take (-8)(-6)=48 Then take 48(-3)= -144 Then take (-144)(-5)= 720 Then take 720(-2)= -1440 Lastly you take (-1440)(-2) and get: 2,880

7 0

4 years ago