Base Surface Area = 2π×132<span> = </span><span>1061.8583169134 in2</span>
<span>Lateral Surface Area = 2π×13×14 = </span><span>1143.5397259067 in2</span>
<span>Total Surface Area = </span><span>2205.39804282 in<span>2</span></span>
Option C:
{x: –1 < x < 7}
Solution:
Given expression is (x – 2 < 5) ∩ (x + 7 > 6).
Let us first solve the inequality.
First inequality:
⇒ x – 2 < 5
Add 2 on both sides of the expression.
⇒ x – 2 + 2 < 5 + 2
⇒ x < 7
Second inequality:
⇒ x + 7 > 6
Subtract 7 on both sides of the expression.
⇒ x + 7 – 7 > 6 – 7
⇒ x + 7 – 7 > 6 – 7
⇒ x > –1
Now to find the intersection of these inequalities.
(x – 2 < 5) ∩ (x + 7 > 6) = (x < 7) ∩ (x > –1)
= (x < 7) ∩ (–1 < x)
= –1 < x < 7
Thus, option C is the correct answer.
(x – 2 < 5) ∩ (x + 7 > 6) = {x: –1 < x < 7}
Do you have the function?
Answer:
sha ba da ba ding dong
Step-by-step explanation:
We know that
the equation of the line in <span>slope-intercept form--------------> y=mx+b
Part A)
</span>Passing through (2,5) and perpendicular to the line whose equation is -3x+y-6=0
<span>Step 1
find the slope m
</span><span>remember that if two lines are perpendicular mi*m2=-1
</span>-3x+y-6=0---------> y=3x+6-------------> m1=3
then
m2=-1/3
Step 2
find the value of b
point (2,5) m=-1/3
y=mx+b----------> 5=(-1/3)*2+b--------> b=5+(2/3)-----> b=17/3
Step 3
find the equation of the line in slope-intercept form
y=(-1/3)x+17/3
using a graph tool
see the attached figure
the answer part A) is y=(-1/3)x+17/3Part B)
Passing through (2,5) and perpendicular to the line whose equation is -3x-6=7x; slope intercept form.
Step 1
-3x-6=7x---------> 10x=-6 -----> x=-6/10-----> x=-3/5 (parallel to the axis y)
equation of the line is a constant so its perpendicular will be another constant defined by the coordinate y of the point through which it passes parallel to the axis x
point (2,5) ----------> the coordinate y=5
therefore
the perpendicular line is y=5 (parallel to the axis x)
using a graph tool
see the attached figure
the answer part B) is y=5