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Ivenika [448]
3 years ago
10

Ceres is BEST classified as a(n) ___.

Physics
2 answers:
DedPeter [7]3 years ago
8 0
Option C.

Ceres is considered the smallest dwarf planet of the solar system.
WINSTONCH [101]3 years ago
7 0

Ceres is best classified as a dwarf planet. Ceres is located in he asteroid belt. Ceres is much closer to Earth than Pluto and it was discovered in the year of 1801.

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If all the stars in an elliptical galaxy traveled random directions in their orbits, the elliptical galaxy would be type
Lemur [1.5K]

The answer would be E7. Galaxies categorized as E0 look to be nearly perfect, while those registered as E7 seem much extended than they are widespread. It is worth noting, though, that a galaxy's look is connected to how it lies on the sky when viewed from Earth. An E7 galaxy is very long and thin or the flattest of them all. 

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3 years ago
HELP WILL MARK BRAINLIEST!!
kherson [118]

Answer:15

Explanation:

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3 years ago
213.49 in standard form is
Rudiy27

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21349/ 100

Explanation:

7 0
3 years ago
Why do the heights of the tides change over the course of a month?
Y_Kistochka [10]

Answer:

The heights of the tides change over the course of a month due to -

<u>the position of Sun , Moon and Earth .</u>

Explanation:

Tides are formed due to the gravitational attraction of the sun and the moon on the surface of the Earth .

Since , the Moon is closer to Earth as compared to the Sun , Hence , Moon has greater attraction on Earth than Sun .

Moon plays an important role for producing the Tides .

In every 27.3 days , the Earth and the Moon revolves around the common point .

Therefore , in every 27.3 days , a new tidal cycle forms .

Two types of tides are possible , high tide and low tides .

In a day , two high tide and two low tide occurs ,

And because of the angle of Moon with respect to Earth , the two high tides do not have the same height . same for the case of two low tide .

The height of tides differ in the height on a daily basis .

5 0
3 years ago
A 19 kg solid disk of radius0.44 m is rotated about an
Vlad1618 [11]

Answer:

0.915 Nm

Explanation:

1 revolution = 2π rad

We can use the following equation of motion to find out the acceleration acting on the disk

\omega^2 - \omega_0^2 = 2\alpha\Delta \theta

where \omega v = 2.5 rad/s is the final angular velocity of the disk, [tex]\omega_0 = 0 rad/s is the initial velocity of the can when it starts from rest, \Delta \theta is the angular distance traveled, \alpha is the angular acceleration of the disk, which we care looking for:

2.5^2 - 0 = 2*\alpha*2\pi

\alpha = \frac{2.5^2}{2*2\pi} \approx 0.5 rad/s^2

The moment of inertia of the solid disk is:

I = \frac{1}{2}mR^2 = \frac{1}{2}19*0.44^2 = 1.8392 kgm^2

where m is the mass and R is the radius of the disk

The net torque applied is

T = \alpha*I = 0.5 * 1.8392 = 0.915 Nm

8 0
3 years ago
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