m = mass of pellet = 2.10 x 10⁻² kg
x = compression of spring at the time launch = 9.10 x 10⁻² m
h = height gained by the pellet above the initial position = 6.10 m
k = spring constant
using conservation of energy
spring potential energy = gravitational potential energy of pellet
(0.5) k x² = m g h
inserting the values
(0.5) k (9.10 x 10⁻²)² = (2.10 x 10⁻²) (9.8) (6.10)
k = 303.2 N/m
You probably do this as a DC circuit which is not quite correct, but it will get you an answer. The study is a great deal more complicated.
Problem One: Secondary Power.
W = E * I
E = 10 A
I = 24V
W = 24 * 10
W = 240 Watts.
Here's the thing you have to know. These transformers are 100% efficient (or are assumed so). So whatever wattage is in the secondary, it is the same as that in the primary.
Primary Power = Secondary Power
Secondary Power = 240 Watts
Primary Power = 240 Watts
W = E * I
E = 240 volts
W = 240 watts
I = W/E = 240 / 240
I = 1 Amp. Answer Part One
Part Two
Answered above. 240 watts.
Part Three
Answered above. 240 watts.
Secondar
Answer:
A: They maintain stable concentrations.
Explanation:
Hopefully this helps!
Answer:
C. the bottom
Explanation:
The tires of the car is rolling without slipping. In this case, the bottom of the tire that contacts the surface must be at rest in order to prevent slipping. Of course this is instantaneously. The tire has a translational velocity, v, and also at the bottom a rotational velocity, -v, and the sum is zero for the bottom.
