How do you do this Problem using factoring (fx)=4x^2-25?

Mathematics

1 answer:

Yanka [14]3 years ago

5 0

Answer: (2x+5)(2x−5)

Step-by-step explanation:For me, what i like to do is to try divide the problem into two parts. For example in this problem, you would divide the 4x^2 into two 4x(since 4x+4x = 4x^2). Then 25 can be divide into into 5s (5x5=25). SInce you know that its a negative 25, you know that it has to be a negative on one of the sides. So the answer in factor form is (2x+5)(2x−5)

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Ten times the square of a non-zero number is equal to fifty times the number. what is the number?

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Reduce to simpleast form. -5/8 - (-4/3)=

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$-\frac{5}{8} -(-\frac{4}{3} )= -\frac{5}{8}^{(3} + \frac{4}{3}^{(8} = \frac{-15+32}{24}= \frac{17}{24}$