How is each function related to y=x

Find the mean and the median of 6 ,5 ,3 ,28, 6 ,4 ,7

kozerog [31]

Mean is 8
you have to add all the numbers and then divide it by the number of elements you have in this case 7

8 0

3 years ago

What is the measure of minor arc ? 17° 75° 149° 211°.

Iteru [2.4K]

The possible measures of the angle at the center of the circle formed by the minor arc are 17°, 75°, and 149°.

<h3>What is the minor and major arc?</h3>

A major arc is an arc in the circle which measures less than 180° at the center of the circle, while a major arc is an arc that measures more than 180° at the center of the circle.

We know about the major and minor arc, therefore, from all the given options, 17°, 75°, and 149° are the measure of the angle that is less than 180°. Thus, these angles are will form the minor arc.

Hence, the possible measures of the angle at the center of the circle formed by the minor arc are 17°, 75°, and 149°.

Learn more about Arc:

brainly.com/question/14732475

8 0

2 years ago

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1-cot^2a+cot^4a=sin^2a(1+cot^6a) prove it.

aliina [53]

Step-by-step explanation:

We have

1-cot²a + cot⁴a = sin²a(1+cot⁶a)

First, we can take a look at the right side. It expands to sin²a + cot⁶(a)sin²(a) = sin²a + cos⁶a/sin⁴a (this is the expanded right side) as cot(a) = cos(a)/sin(a), so cos⁶a = cos⁶a/sin⁶a. Therefore, it might be helpful to put everything in terms of sine and cosine to solve this.

We know 1 = sin²a+cos²a and cot(a) = cos(a)/sin(a), so we have

1-cot²a + cot⁴a = sin²a+cos²a-cos²a/sin²a + cos⁴a/sin⁴a

Next, we know that in the expanded right side, we have sin²a + something. We can use that to isolate the sin²a. The rest of the expanded right side has a denominator of sin⁴a, so we can make everything else have that denominator.

sin²a+cos²a-cos²a/sin²a + cos⁴a/sin⁴a

= sin²a + (cos²(a)sin⁴(a) - cos²(a)sin²(a) + cos⁴a)/sin⁴a

We can then factor cos²a out of the numerator

sin²a + (cos²(a)sin⁴(a) - cos²(a)sin²(a) + cos⁴a)/sin⁴a

= sin²a + cos²a (sin⁴a-sin²a+cos²a)/sin⁴a

Then, in the expanded right side, we can notice that the fraction has a numerator with only cos in it. We can therefore write sin⁴a in terms of cos (we don't want to write the sin²a term in terms of cos because it can easily add with cos²a to become 1, so we can hold that off for later) , so

sin²a = (1-cos²a)

sin⁴a = (1-cos²a)² = cos⁴a - 2cos²a + 1

sin²a + cos²a (sin⁴a-sin²a+cos²a)/sin⁴a

= sin²a + cos²a (cos⁴a-2cos²a+1-sin²a+cos²a)/sin⁴a

= sin²a + cos²a (cos⁴a-cos²a+1-sin²a)/sin⁴a

factor our the -cos²a-sin²a as -1(cos²a+sin²a) = -1(1) = -1

sin²a + cos²a (cos⁴a-cos²a+1-sin²a)/sin⁴a

= sin²a + cos²a (cos⁴a-1 + 1)/sin⁴a

= sin²a + cos⁶a/sin⁴a

= sin²a(1+cos⁶a/sin⁶a)

= sin²a(1+cot⁶a)

8 0

3 years ago

If a fourth plant produces 400 widgets in 60 days, which statement is true?

USPshnik [31]

The complete question in the attached figure

the statements are
1) It makes less than plant B
2) It makes the same as plant A
3) It makes more than plant C

we know that
<span>analyzing the graph

</span>plant A
for x=40 y=100
for x=50 y=200
that means
the production in 10 days is 100 widgets
then
the production in 60 days will be 6*100----> 600 widgets
so
plant A production > plant fourth production
plant fourth production < plant A production

plant B
for x=40 y=0
for x=60 y=100
that means
the production in 20 days is 100 widgets
then
the production in 60 days will be 3*100----> 300 widgets
so
plant B production < plant fourth production
plant fourth production > plant B production

plant C
for x=20 y=0
for x=40 y=100
that means
the production in 20 days is 100 widgets
then
the production in 60 days will be 3*100----> 300 widgets
plant C production < plant fourth production
or
plant fourth production > plant C production

therefore

the answer is
3) It makes more than plant C

7 0

3 years ago

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Wilma can mow a lawn in 80 mintues.Melissa can mow the same lawn in 120 minutes. How long does it take for both Wilma and Meliss

Luba_88 [7]

There is a formula for that;
Total time = (Worker 1 * Worker 2) / (Worker 1 + Worker 2)
Total time = (80 * 120) / (80 + 120)
Total time = 9,600 / 200
Total time = 48 minutes

4 0

3 years ago