Answer: √y
<u>Step-by-step explanation:</u>
![\sqrt[6]{y^3}=y^{\frac{3}{6}}=y^{\frac{1}{2}}=\boxed{\sqrt y}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7By%5E3%7D%3Dy%5E%7B%5Cfrac%7B3%7D%7B6%7D%7D%3Dy%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cboxed%7B%5Csqrt%20y%7D)
Answer:
10.5
Step-by-step explanation:
Break the problem down into small parts:
2 to the power of 3= 8
8+7+6=
15+6=21
21/2
21 divided by 2 is 10.5
Hope this helps!
That is where the line crosses the x axis or where y=0
0=-16x^2+22x+3
we gon do grouping
ac method
-16 times 3=-48
what 2 numbers multiply to get -48 and add to get 22
-2 and 24
0=-16x^2-2x+24x+3
group
0=(-16x^2-2x)+(24x+3)
undistribute
0=-2x(8x+1)+3(8x+1)
undistribute
0=(8x+1)(-2x+3)
set eaqual to 0
8x+1=0
8x=-1
x=-1/8
-2x+3=0
3=2x
3/2=x
x intercepts ate x=-1/8 and x=3/2