I think the statement given above is false. Panes created using the vertical split bar do not scroll together horizontally. <span>The two </span>panes scroll together vertically, but scroll<span> independently </span>horizontally<span>. Hope this answers the question. Have a nice day.</span>
C. It's honestly up to the user, upload so others can use it or make it so its copyrighted and make some cash :P
Technology is a useful tool for research. It is how we drive around. Technology is important for medicinal purposes.
lol
Answer:
a) Custom AppExchange-app for product-pricing
Explanation:
We can find a solution in AppExchange for this product-pricing, surfing in the option, we could get solutions like BoonPlus, and easy pricing Opportunity, this App has a free trial.
With this option is easy to choose a book price, add new products, select pricing rule, we can get an order's product, and calculate pricing, just we must download the app and install it.
Answer:
# include <iostream.h>
# include <stdio.h>
# include <string.h>
using namespace std;
class citizen
{
int i;
public string name[30];
public long int phonenumber[30];
public void addindividual(string name1)
{
If (i<=30)
{ int flag=0;
for(int j=0; j<=i;j++)
{
if (strcmp(name[i], name1)
{
flag=1;
}
else
{
flag=0;
}
}
If (flag)
{
if (i<30)
{
for(j=i+1;j<=30; j++)
{
cout<<"Enter the name:"; getchar(name[j]);
cout<<"Enter the phone number:"; cin>>phonenumber[j];
i++;
}
else
{
cout<<"The person already exists";
exit();
}
}
else
{
cout<<"array is full:";
exit();
}
}
}
Void main()
{
string str;
cout<<" Enter name:";
getline(cin, str); ;
citizen c1=new citizen();
c1.addindividual(name1);
}
Explanation:
With a little more effort you can make the program allow the user to enter any number of details, but less than 30 overall. We have used here flag, and as a programmer we know why we use the Flag. It is used to check whether certain Boolean condition is fulfilled or not. Here, we are checking whether a given name is present in the array of names, and if it is not present, we add that to the list. And if the name is present, we print, it already exist.
